PHP提交表单失败后如何保留已经填写的信息_PHP
本文介绍PHP提交表单失败后如何保留填写的信息一些方法总结，其中最常用的就是使用缓存方式了，这种方法如果网速慢是可能出问题的，最好的办法就是使用ajax了。
1．使用header头设置缓存控制头Cache-control。
PHP代码如下：
header('Cache-control: private, must-revalidate'); //支持页面回跳
2．使用session_cache_limiter方法。
PHP代码如下：
session_cache_limiter('private, must-revalidate'); //要写在session_start方法之前
下面介绍一下session_cache_limiter参数：
session_cache_limiter内的几个参数意义是：
nocache：当然是不缓存（比如：表单信息被清除），但公共变量可以缓存
private：私有方式缓存（比如：表单信息被保留，但在生存期内有效）
private_no_cache：私有方式但不过期（表单信息被保留）
publice：公有方式，（表单信息也被保留）
设置缓存过期时间：session_cache_expire函数设置，缺省是180分钟。
常遇见问题：
1.session_cache_limiter("private");表单信息是保留了,但是如果我修改已经提交的信息,表单页面所呈现的信息还是缓存里信息,没能及时自动刷新,如果不用session_cache_limiter("private");又不能保留表单信息
解决方案：
在session_start前面加上
session_cache_limiter( "private, must-revalidate" );
即可。
2.另一种办法我们可以使用ajax来实例
index.html模板文件大致内容如下：
<html>
<head>
<title>jQuery Ajax 实例演示</title>
</head>
<script src="./js/jquery.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function(){//这个就是jQueryready ，它就像C语言的main 所有操作包含在它里面
$("#button_login").mousedown(function(){
login(); //点击ID为"button_login"的按钮后触发函数 login();
});
function login(){ //函数 login();
var username = $("#username").val();//取框中的用户名
var password = $("#password").val();//取框中的密码
$.ajax({ //一个Ajax过程
type: "post", //以post方式与后台沟通
url : "login.php", //与此php页面沟通
dataType:'json',//从php返回的值以 JSON方式 解释
data: 'username='+username+'&password='+password, //发给php的数据有两项，分别是上面传来的u和p
success: function(json){//如果调用php成功
//alert(json.username+'n'+json.password); //把php中的返回值（json.username）给 alert出来
$('#result').html("姓名:" + json.username + "<br/>密码:" + json.password); //把php中的返回值显示在预定义的result定位符位置
}
});
}
//$.post()方式：
$('#test_post').mousedown(function (){
$.post(
'login.php',
{
username:$('#username').val(),
password:$('#password').val()
},
function (data) //回传函数
{
var myjson='';
eval_r('myjson=' + data + ';');
$('#result').html("姓名1:" + myjson.username + "<br/>密码1:" + myjson.password);
}
);
});
//$.get()方式：
$('#test_get').mousedown(function (){
$.get(
'login.php',
{
username:$('#username').val(),
password:$('#password').val()
},
function(data) //回传函数
{
var myjson='';
eval_r("myjson=" + data + ";");
$('#result').html("姓名2:" + myjson.username + "<br/>密码2:" + myjson.password);
}
);
});
});
</script>
<body>
<div id="result" style="background:orange;border:1px solid red;width:300px;height:200px;"></div>
<form id="formtest" action="" method="post">
<p><span>输入姓名:</span><input type="text" name="username" id="username" /></p>
<p><span>输入密码:</span><input type="text" name="password" id="password" /></p>
</form>
<button id="button_login">ajax提交</button>
<button id="test_post">post提交</button>
<button id="test_get">get提交</button>
</body>
</html>
login.php文件的内容如下：
<?php
echo json_encode(array ('username'=>$_REQUEST['username'],'password'=>$_REQUEST['password']));
?>
这样的话我们提交不需要刷新页面了，如果失败就直接会有提交了，这样可以100%保存提交失败后数据不被丢失了。
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