Table of Contents
1) Typedef basic data types take "aliases"" >1) Typedef basic data types take "aliases"
4) typedef takes the "alias" for the pointer " >4) typedef takes the "alias" for the pointer
Traps in typedef" >Traps in typedef
" >#4) typedef принимает «псевдоним» для указателя
Home Common Problem What are the usages of typedef

What are the usages of typedef

Jun 07, 2023 am 10:38 AM
c language typedef usage

Typedef usage includes: 1. Typedef basic data types take "aliases". All data types in C language can use typedef to redefine type names; 2. Typedef takes "aliases" for custom data types. Customized data types include: structure struct name { };, union unit name { };, enumeration enum { }; 3. Typedef takes "aliases" for arrays; 4. Typedef takes "aliases" for pointers.

What are the usages of typedef

#The operating environment of this article: Windows 10 system, C 20 version, dell g3 computer.

##In practical applications, typedef mainly has the following four uses:

1) Typedef basic data types take "aliases"
That is to say, all data types in C language can use the typedef keyword to redefine the type name

typedef unsigned int size;typedef unsigned int16 u16;typedef unsigned int8 u8;...
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2) typedef takes an "alias" for the custom data type
Custom data types include: structure struct name{ };, union unit name { };, enumeration enum { };

struct students{
	char sex;
	char name[120];
	int ages;};
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Commonly used methods for redefining data names for structures are:

struct students{
	char sex;
	char name[120];
	int ages;}std;std.name[20]="wujunwu"
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In addition, typedef can also be used to define:

struct students{
	char sex;
	char name[120];
	int ages;};typedef struct students std;std.name[20]="wujunwu"
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3) typedef is The array takes an "alias"
typedef char arr_name[20];arr_name ane; ane[20]="wujunwu"
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4) typedef takes the "alias" for the pointer
ordinary pointer
int a=2;int* pointer;pointer =&a;
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is equivalent to :

int a=2;typedef int* pointer;pointer p;p=&a;
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If the data type of a is char, that is, char a =2; then,

char a=2;typedef int* pointer;pointer p;p=&(pointer)a;
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Function pointer
typedef unsigned int bool;typedef bool(*pCopySDMMC2Mem)(int, unsigned int, unsigned short, unsigned int*, bool);typedef void (*pBL2Type)(void);pCopySDMMC2Mem p1=(pCopySDMMC2Mem)0xD0037F98;pBL2Type p2 = (pBL2Type)0x23E00000;
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In fact, the above program is executed Two steps:

The first step: Give the pointer an "alias"

pCopySDMMC2Mem p1;pBL2Type p2;
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The second step: Forced type conversion

(pCopySDMMC2Mem)0xD0037F98;  //真正在写代码时不能这样写(pBL2Type)0x23E00000;
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The third step: Assign a value to the pointer

p1=(pCopySDMMC2Mem)0xD0037F98;p2 = (pBL2Type)0x23E00000;
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Summary: When using typedef, typedef does not create any new types. It just provides an "alias" for an existing type for use in the program.

Traps in typedef

Next look at a simple typedef usage example, as shown in the following code:

typedef char* PCHAR;int strcmp(const PCHAR,const PCHAR);
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In the above code , is "const PCHAR" equivalent to "const char*"?

The answer is no. The reason is very simple. Typedef is used to define a new alias of a type. It is different from a macro and is not a simple string replacement. Therefore, the const in "const PCHAR" gives the entire pointer itself constantness, which forms the constant pointer "char* const (a constant pointer pointing to char)". That is, it is actually equivalent to "char* const", not "const char* (pointer to constant char)". Of course, it is also easy to make const PCHAR equivalent to const char*, as shown in the following code:

typedef const char* PCHAR;int strcmp(PCHAR, PCHAR);
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In fact, whenever a typedef is declared for a pointer, it should be in the final typedef name Add a const to make the pointer itself a constant.

It is also important to note that although typedef does not really affect the storage characteristics of the object, it is still a storage class keyword in syntax, just like the keywords such as auto, extern, static and register. . Therefore, the following declaration method is not feasible:

typedef static int INT_STATIC;
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The reason why it is not feasible is that multiple storage class keywords cannot be declared, because typedef has already occupied the position of the storage class keyword, so in typedef You can no longer use static or any other storage class keyword in the declaration. Of course, the compiler will also report an error. For example, the error message in VC 2010 is "Cannot specify multiple storage classes."

Разница между typedef и #define:

(1) Имя символа, созданное typedef ограничено типом, а не значением

(2) typedef интерпретируется компилятором, а не препроцессором

Четыре использования typedef

В практических приложениях , typedef В основном существует четыре варианта использования:

1) Базовые типы данных Typedef принимают «псевдонимы»

То есть все типы данных в языке C могут использовать typedef Ключевые слова для переопределения имени типа
typedef unsigned int size;typedef unsigned int16 u16;typedef unsigned int8 u8;...
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2) typedef принимает «псевдоним» для пользовательского типа данных

К настраиваемым типам данных относятся: структура struct name{ };, имя единицы объединения { };, перечисление enum { };

struct students{
	char sex;
	char name[120];
	int ages;};
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Обычно используемые методы переопределения имен данных для структур:

struct students{
	char sex;
	char name[120];
	int ages;}std;std.name[20]="wujunwu"
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Кроме того, typedef также можно использовать для определения:
struct students{
	char sex;
	char name[120];
	int ages;};typedef struct students std;std.name[20]="wujunwu"
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3) typedef принимает «псевдоним» для массива
typedef char arr_name[20];arr_name ane; ane[20]="wujunwu"
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#4) typedef принимает «псевдоним» для указателя

Обычный указатель

int a=2;int* pointer;pointer =&a;
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эквивалентен:

int a=2;typedef int* pointer;pointer p;p=&a;
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Если тип данных a — char, то есть char a =2; тогда
char a=2;typedef int* pointer;pointer p;p=&(pointer)a;
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Указатель функции

typedef unsigned int bool;typedef bool(*pCopySDMMC2Mem)(int, unsigned int, unsigned short, unsigned int*, bool);typedef void (*pBL2Type)(void);pCopySDMMC2Mem p1=(pCopySDMMC2Mem)0xD0037F98;pBL2Type p2 = (pBL2Type)0x23E00000;
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На самом деле приведенная выше программа выполняет два шага:

Первый шаг: присвойте указателю «псевдоним»

pCopySDMMC2Mem p1;pBL2Type p2;
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Второй шаг: принудительное преобразование типов

(pCopySDMMC2Mem)0xD0037F98;  //真正在写代码时不能这样写(pBL2Type)0x23E00000;
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Шаг 3. Присвоение значения указателю

p1=(pCopySDMMC2Mem)0xD0037F98;p2 = (pBL2Type)0x23E00000;
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Краткое описание: При использовании typedef typedef не создает новый тип, а просто предоставляет «псевдоним». " для существующего типа, чтобы его можно было использовать в программе.

Ловушки в typedef

Далее рассмотрим простой пример использования typedef, как показано в следующем коде:

typedef char* PCHAR;int strcmp(const PCHAR,const PCHAR);
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В приведенном выше коде «const PCHAR» эквивалентен «const char*»?

Ответ - нет. Причина очень проста. Typedef используется для определения нового псевдонима типа. Он отличается от макроса и не является простой заменой строки. Следовательно, const в «const PCHAR» придает константность всему указателю, который образует постоянный указатель «char* const (постоянный указатель, указывающий на char)». То есть на самом деле это эквивалентно «char* const», а не «const char* (указатель на константу char)». Конечно, также легко сделать const PCHAR эквивалентным const char*, как показано в следующем коде:

typedef const char* PCHAR;int strcmp(PCHAR, PCHAR);
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Фактически, всякий раз, когда для указателя объявляется определение типа, оно должно быть в конечном определении типа. name Добавьте константу, чтобы сделать сам указатель константой.

Также важно отметить, что хотя typedef на самом деле не влияет на характеристики хранения объекта, в синтаксисе он по-прежнему является ключевым словом класса хранения, как и такие ключевые слова, как auto, extern, static и Register. . Следовательно, следующий метод объявления невозможен:

typedef static int INT_STATIC;
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###Причина, по которой он невозможен, заключается в том, что невозможно объявить несколько ключевых слов класса хранения, поскольку typedef уже занял позицию ключевого слова класса хранения, поэтому в typedef Вы больше не можете использовать статическое или любое другое ключевое слово класса хранения в объявлении. Конечно, компилятор также сообщит об ошибке.Например, сообщение об ошибке в VC 2010: «Невозможно указать несколько классов хранения». ###

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