How to determine whether a parameter is in an array in php
To determine whether a parameter is in a PHP array, you can use the in_array() function. The syntax of this function is as follows:
bool in_array ( mixed $needle , array $haystack [, bool $strict = FALSE ] )
This function accepts three parameters:
-
needle
: The value to be found -
haystack
: Array to find -
strict
: Optional parameter, if set to true, the type will be considered when comparing values
if specified Returns true if the $needle value is found in the $haystack array, otherwise returns false.
The following is an example:
$fruits = array("apple", "banana", "orange", "pear"); if (in_array("apple", $fruits)) { echo "苹果在水果篮子里"; } else { echo "苹果没有在水果篮子里"; }
The above code output:
苹果在水果篮子里
If the value to be checked is a number, strict mode must be used. The following is an example:
$numbers = array(1, 3, 5, 7); if (in_array("3", $numbers, true)) { echo "3在数字数组里(使用严格模式)"; } else { echo "3没有在数字数组里(使用严格模式)"; }
The above code output:
3没有在数字数组里(使用严格模式)
If the value to be checked is a string, you can do it without using strict mode. The following is an example:
$alphabets = array("a", "b", "c", "d"); if (in_array("A", $alphabets)) { echo "A在字母数组里(不使用严格模式)"; } else { echo "A没有在字母数组里(不使用严格模式)"; }
The above code output:
A没有在字母数组里(不使用严格模式)
In short, to determine whether a parameter is in an array in PHP, you can use the in_array() function. This function is simple and ensures that the types of values match by setting a strict mode.
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