Let's talk about flipping linked lists in golang

The linked list is a basic data structure, which is composed of some nodes. Each node contains a data field and a pointer to the next node. In programming, it is often necessary to operate on linked lists, and one of the most basic operations is to flip the linked list.

Flipping the linked list means reversing the order of the nodes in the linked list. For example, the original linked list is 1->2->3->4, but after flipping it, it becomes 4->3->2->1. In practical applications, flipping the linked list can be used to solve some problems, such as printing the elements in the linked list, finding the intermediate nodes of the linked list, determining whether there is a cycle in the linked list, etc.

In this article, we will introduce how to use the golang programming language to implement the flipping of a linked list. First, we need to define a structure Node of a linked list node:

type Node struct {
    Value int
    Next *Node
}

In this structure, Value represents the data stored in the linked list node, and Next is a pointer to the next node. After having the node structure, we can define the linked list structure:

type List struct {
    Head *Node
}

In this structure, Head is a pointer to the head node of the linked list.

Next, let’s take a look at the code for how to implement a flipped linked list:

func (l *List) Reverse() {
    if l.Head == nil || l.Head.Next == nil {
        return
    }

    var prev *Node
    current := l.Head
    for current != nil {
        next := current.Next
        current.Next = prev
        prev = current
        current = next
    }
    l.Head = prev
}

In this code, first determine whether the linked list is empty or has only one node, and if so, return directly No flipping is performed. If not, define two pointers, prev and current, which point to the previous node and current node of the linked list respectively. In the loop, first save the node next to the current node, point the current node to the previous node, and then move the pointer backward. Finally, point the head of the linked list to the last node prev after flipping.

Next, let us look at a complete example to better understand the process of linked list flipping:

package main

import "fmt"

type Node struct {
    Value int
    Next *Node
}

type List struct {
    Head *Node
}

func (l *List) Add(value int) {
    node := &Node{Value: value, Next: l.Head}
    l.Head = node
}

func (l *List) Reverse() {
    if l.Head == nil || l.Head.Next == nil {
        return
    }

    var prev *Node
    current := l.Head
    for current != nil {
        next := current.Next
        current.Next = prev
        prev = current
        current = next
    }
    l.Head = prev
}

func (l *List) Print() {
    var node *Node
    for node = l.Head; node != nil; node = node.Next {
        fmt.Print(node.Value, "->")
    }
    fmt.Println()
}

func main() {
    l := &List{}
    l.Add(1)
    l.Add(2)
    l.Add(3)
    l.Add(4)

    fmt.Println("Original List:")
    l.Print()

    l.Reverse()

    fmt.Println("Reversed List:")
    l.Print()
}

In this example, we define a linked list l, to which we add 4 nodes are then flipped and output. The running results are as follows:

Original List:
4->3->2->1->
Reversed List:
1->2->3->4->

As you can see, the process of flipping the linked list is very simple. You only need to loop through the linked list and reverse the pointers one by one.

In practical applications, linked list flipping is a very common problem, so you need to master this skill. I hope this article can help readers better understand the process of linked list flipping and related programming skills.

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