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Java implements the operation of removing elements from a linked list

Jan 04, 2021 am 11:54 AM
java element linked list

Java implements the operation of removing elements from a linked list

Purpose: Remove linked list elements

(Learning video sharing: java teaching video)

Problem introduction:

Delete all nodes in the linked list that are equal to the given value * "val*".

Example description:

示例:
 
输入: 1->2->6->3->4->5->6, val = 6
输出: 1->2->3->4->5
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Problem solution ideas:

One is based on the sentinel node method, and the other is based on the java collection method. The essence is still the same.

Program implementation:

 import java.util.*;
 
public class RemoveElementsTest3 {
    public static void main(String[] args) {
        ListNode l1 = new ListNode(1);
        ListNode l2 = new ListNode(2);
        ListNode l3 = new ListNode(6);
        ListNode l4 = new ListNode(3);
        ListNode l5 = new ListNode(4);
        ListNode l6 = new ListNode(5);
        ListNode l7 = new ListNode(6);
        l1.next = l2;
        l2.next = l3;
        l3.next = l4;
        l4.next = l5;
        l5.next = l6;
        l6.next = l7;
        ListNode listNode = removeElements2(l1, 6);
        System.out.println("listNode = " + listNode);
 
    }
 
    public static ListNode removeElements(ListNode head, int val) {
        ListNode dummyNode = new ListNode(0);
        ListNode currentNode = dummyNode;
        while (head != null) {
            if (head.val != val) {
                currentNode.next = head;
                currentNode = currentNode.next;
            }
            head = head.next;
        }
        currentNode.next = null;
        return dummyNode.next;
    }
 
    public static ListNode removeElements2(ListNode head, int val) {
        List<Integer> list = new LinkedList<>();
        while (head != null) {
            list.add(head.val);
            head = head.next;
        }
        List<Integer> tempList = new ArrayList<>();
        tempList.add(val);
        list.removeAll(tempList);
        ListNode dummyNode = new ListNode(0);
        ListNode tempNode = dummyNode;
        for (int i = 0, size = list.size(); i < size; i++) {
            ListNode listNode = new ListNode(list.get(i));
            tempNode.next = listNode;
            tempNode = tempNode.next;
        }
        return dummyNode.next;
    }
}
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Summary:

Actually, after writing this, I think it is easy to understand if you look at the implementation logic of the entire program. There is nothing wrong with it. The difficult points need to be deduced. If you don't understand, you can debug the given program multiple times. The content output each time is output only after it is successfully run.

Related recommendations: java introductory tutorial

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