


Wildcards and regular expressions under linux
Regular expressions match qualified strings in files. This article will introduce wildcards and regular expressions under Linux to you. Friends who need it can refer to it
Wildcard
* Any character , can be repeated multiple times
? Any character, repeated once
[] represents a character
Example: [a,b,c] represents any
wildcard in abc
Regular expression used to match file names
Regular expression is used to match qualified strings in files
ls find cp does not support regular expressions
But grep awk sed supports regular expressions
[root@hadoop-bigdata01 test]# touch aa
[ root@hadoop-bigdata01 test]# touch aab aabb
[root@hadoop-bigdata01 test]# ll
total 0
-rw-r--r-- 1 root root 0 May 16 19:47 aa
-rw-r--r-- 1 root root 0 May 16 19:47 aab
-rw-r--r-- 1 root root 0 May 16 19:47 aabb
[root @hadoop-bigdata01 test]# ls aa
aa
[root@hadoop-bigdata01 test]# ls aa?
aab
[root@hadoop-bigdata01 test]# ls aa*
aa aab aabb
Regular expression special characters
Regular expression matching range
Regular expression Expression standard characters
Use regular expression
grep "1" /etc/passwd
Lines containing keyword 1, grep only needs to contain it , do not want wildcards, want to be completely consistent
##
[root@hadoop-bigdata01 test]# grep "1" /etc/passwd bin:x:1:1:bin:/bin:/sbin/nologin mail:x:8:12:mail:/var/spool/mail:/sbin/nologin uucp:x:10:14:uucp:/var/spool/uucp:/sbin/nologin operator:x:11:0:operator:/root:/sbin/nologin games:x:12:100:games:/usr/games:/sbin/nologin gopher:x:13:30:gopher:/var/gopher:/sbin/nologin ftp:x:14:50:FTP User:/var/ftp:/sbin/nologin dbus:x:81:81:System message bus:/:/sbin/nologin usbmuxd:x:113:113:usbmuxd user:/:/sbin/nologin avahi-autoipd:x:170:170:Avahi IPv4LL Stack:/var/lib/avahi-autoipd:/sbin/nologin abrt:x:173:173::/etc/abrt:/sbin/nologin wang:x:501:501::/home/wang:/bin/bash grep 'root' /etc/passwd cat /etc/passwd | grep 'root'
##
grep '[0-9]' /etc/passwd
2. Match lines containing three consecutive numbers
grep '[0-9][0-9][0-9]' /etc/passwd 或者 grep ':[0-9][0-9][0-9]:' /etc/passwd
[root@hadoop-bigdata01 test]# grep '[0-9][0-9][0-9]' /etc/passwd games:x:12:100:games:/usr/games:/sbin/nologin usbmuxd:x:113:113:usbmuxd user:/:/sbin/nologin rtkit:x:499:497:RealtimeKit:/proc:/sbin/nologin avahi-autoipd:x:170:170:Avahi IPv4LL Stack:/var/lib/avahi-autoipd:/sbin/nologin abrt:x:173:173::/etc/abrt:/sbin/nologin nfsnobody:x:65534:65534:Anonymous NFS User:/var/lib/nfs:/sbin/nologin saslauth:x:498:76:"Saslauthd user":/var/empty/saslauth:/sbin/nologin pulse:x:497:496:PulseAudio System Daemon:/var/run/pulse:/sbin/nologin liucheng:x:500:500::/home/liucheng:/bin/bash wang:x:501:501::/home/wang:/bin/bas
3. Match lines starting with r and ending with n
grep '^r.*n$' /etc/passwd .*代表所有 [root@hadoop-bigdata01 test]# grep '^r.*n$' /etc/passwd rpc:x:32:32:Rpcbind Daemon:/var/cache/rpcbind:/sbin/nologin rtkit:x:499:497:RealtimeKit:/proc:/sbin/nologin rpcuser:x:29:29:RPC Service User:/var/lib/nfs:/sbin/nologin
4. Filter ifconfig, Intercept ip
grep -v represents reverse interception, which means to remove the lines with a certain keyword sed means replacement
[root@hadoop-bigdata01 test]# ifconfig | grep 'inet addr:' inet addr:192.168.126.191 Bcast:192.168.126.255 Mask:255.255.255.0 inet addr:127.0.0.1 Mask:255.0.0.0 [root@hadoop-bigdata01 test]# [root@hadoop-bigdata01 test]# ifconfig | grep 'inet addr:' | grep -v '127.0.0.1' inet addr:192.168.126.191 Bcast:192.168.126.255 Mask:255.255.255.0 [root@hadoop-bigdata01 test]# ifconfig | grep 'inet addr:' | grep -v '127.0.0.1' | sed 's/inet addr://g' 192.168.126.191 Bcast:192.168.126.255 Mask:255.255.255.0 [root@hadoop-bigdata01 test]# ifconfig | grep 'inet addr:' | grep -v '127.0.0.1' | sed 's/inet addr://g' | sed 's/Bcast.*//g' 192.168.126.191
MisunderstandingThere is a misunderstanding here. I have thought about it for a long time. It is the difference between regular expressions and wildcards
We know that the wildcard * refers to Any character can be repeated multiple times. The * in the regular expression refers to matching the previous character >= 0 times.
These two are completely different. So how do I know whether the * I use is a wildcard or a regular expression? Formula
At first I fell into a misunderstanding. Look at the following series of commands
[root@hadoop-bigdata01 test]# touch ac aac abc abbc [root@hadoop-bigdata01 test]# ll total 0 -rw-r--r-- 1 root root 0 May 16 19:55 aac -rw-r--r-- 1 root root 0 May 16 19:55 abbc -rw-r--r-- 1 root root 0 May 16 19:55 abc -rw-r--r-- 1 root root 0 May 16 19:55 ac [root@hadoop-bigdata01 test]# ls | grep 'a*c' aac abbc abc ac [root@hadoop-bigdata01 test]# ls | grep 'a.*c' aac abbc abc ac [root@hadoop-bigdata01 test]# ls | grep '^a.*c' aac abbc abc ac [root@hadoop-bigdata01 test]# ls | grep '^a*c' aac ac
Why grep 'a*c' and grep '^a*c$' The results will be different. I thought one was a wildcard and the other was a regular expression, because the four results displayed by a*c happened to be
. Doesn’t it match any number of characters?
is actually not the case.
The wildcard is used to match the file name.
The regular expression is to match the string that meets the conditions in the file.
Use grep after passing it to the pipe character. It's not matching file names, it's an operation on files, so it's completely a regular expression.
grep 'a*c' means matching a>=0, so it's OK as long as it contains c.
And grep '^a*c$' is also a regular pattern, which means it starts with a, and the second character matches a zero or more times, followed by the letter c
So only aac and ac meet the conditions
So look at this example
[root@hadoop-bigdata01 test]# ls a aac abb abbc abc ac b bb c cb [root@hadoop-bigdata01 test]# ls | grep 'a*b' abb abbc abc b bb cb
Here grep 'a*b' does not refer to a and b but a is repeated 0 or more times and then contains b
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