Home Java javaTutorial How to handle special character escaping using Java regular expressions

How to handle special character escaping using Java regular expressions

Jan 16, 2017 am 11:11 AM

正则需要转义字符

'$', '(', ')', '*', '+', '.', '[', ']', '?', '\\', '^', '{', '}', '|'

异常现象:

java.util.regex.PatternSyntaxException: Dangling meta. character '*' near index 0

解决方法

对特殊字符加\\转义即可。

注意:虽然使用[]在部分条件下也可以,但是在对于(、[、{范围边界开始符不匹配的情况下会报如下:

异常现象

java.util.regex.PatternSyntaxException: Illegal repetition near index 50

Java过滤正则表达式特殊字代码如下(注意:\\需要第一个替换,否则replace方法替换时会有逻辑bug)

/**
 * 转义正则特殊字符 ($()*+.[]?\^{},|)
 *
 * @param keyword
 * @return
 */
public static String escapeExprSpecialWord(String keyword) {
 if (StringUtils.isNotBlank(keyword)) {
 String[] fbsArr = { "\\", "$", "(", ")", "*", "+", ".", "[", "]", "?", "^", "{", "}", "|" };
 for (String key : fbsArr) {
 if (keyword.contains(key)) {
 keyword = keyword.replace(key, "\\" + key);
 }
 }
 }
 return keyword;
}
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总结

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