


The return value of php exec cannot be negative in Linux_PHP Tutorial
The return value of php exec in Linux cannot be a negative number. Friends in need can refer to it.
Let’s first learn about how to use the exec function
exec()
Prototype:
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string exec (string command [, string array [ , int return_var]])
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The exec () function is similar to system (). It also executes the given command, but does not output the result, but returns the last line of the result. Although it only returns the last line of the command result, using the second parameter array can get the complete result by appending the results line by line to the end of the array. So if the array is not empty, it is best to use unset() to clear it before calling it. Only when the second parameter is specified, the third parameter can be used to obtain the status code of command execution.
Example:
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exec("/bin/ls -l" );
exec("/bin/ls -l", $res, $rc); |
The third parameter, why can’t it receive negative numbers??
The &$return_var here is the program return value. At first, my answer was that it can be a negative number. Generally in C language we would write like this
代码如下 | 复制代码 |
#include #include int main() { printf("^_^n"); return -5; } |
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#include
#include Return -5; }
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This -5 is the return value, but it is customary to write it as 0 or 1.
Note: Many people write the main function as void main() in their C code. This is actually wrong, so I won’t go into details.
代码如下 | 复制代码 |
exec("/home/wwwroot/test/rtest.out 2>&1",$out,$a); var_dump($out,$a); array(1) { [0]=> string(3) "^_^" } int(251) |
The code is as follows | Copy code |
E:devphp535>php -r "exec( 'return.exe',$out,$a);var_dump($a);" |
The code is as follows | Copy code |
exec("/home/wwwroot/test/ rtest.out 2>&1",$out,$a); var_dump($out,$a); array(1) { [0]=> string(3) "^_^" } int(251) |
It looks like 256+return val. You can see that a negative number is actually returned, but it is converted into a positive number.
Then I looked at the source code in standard/exec.c, and found no clues. It was very strange, and suddenly I realized that I had forgotten a step. Forgot to look at the value returned by the program to the OS.
You can use echo $? to display the status of the last command.
The code is as follows
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Copy code
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-bash-3.00$ vi main.c
-bash-3.00$ gcc -o ./mm main.c -bash-3.00$ ll total 48drwxr-xr-x 3 www www 4096 May 4 2011 2011 drwxr-xr-x 6 www www 4096 Jun 23 2011 eoc |
-rwxr-xr-x 1 www www 7131 Feb 1 12:47 hello
drwxr-xr-x 3 www www 4096 Jun 24 2011 test

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