怎么生成静态页面
比方说
-
'.$row['xiaofenleiindex'].'
';
require_once('gongxiang.php');
$con = lianjie();
$result = mysql_query("SELECT * FROM tupianwenzi left join detail on tupianwenzi.xiaofenleiindex = detail.xiaofenleidetail");
while($row = mysql_fetch_array($result))
{
echo'
}
?>
mysql_close($con);
?>
这个代码 用什么方法生成静态页面 最好 最快
回复讨论(解决方案)
无解。。。生成不了
生成不了?????
我觉得 直接把 最终的网页源代码复制出来最快了啊 PHP有没有这种写法。。
在文件开始出加入
<?phpfunction callback($buffer) { file_put_contents('你需要的文件名', $buffer); return $buffer; //不需显示页面内容就 return '';}ob_start("callback");?>
function callback($buffer) {
file_put_contents('111.html', $buffer);
return $buffer; //不需显示页面内容就 return '';
}
ob_start("callback");
?>
echo'wee';
?>
这样写 不会生成111.html
function callback($buffer) {
file_put_contents('111.html', $buffer);
return $buffer; //不需显示页面内容就 return '';
}
ob_start("callback");
?>
echo'wee';
?>
这样写 不会生成11……
你得引用这个函数啊,这个自定义函数不得使用才行啊
function callback($buffer) {
file_put_contents('111.html', $buffer);
return $buffer; //不需显示页面内容就 return '';
}
ob_start("callback");
?>
echo'wee';
?>
这样写 不会生成11…… 噢,php 已被改得面目全非了。
加个参数
ob_start("callback", PHP_OUTPUT_HANDLER_START);
以前是不要的
引用 5 楼 aaa86965921aaa 的回复: function callback($buffer) {
file_put_contents('111.html', $buffer);
return $buffer; //不需显示页面内容就 return '';
}
ob_start("callback");
?>
ec……
$buffer 参数写什么 能不能写个能用的给我。。
这样就行,已通过测试
function callback($buffer) { file_put_contents('你需要的文件名', $buffer); return $buffer; //不需显示页面内容就 return '';}ob_start("callback", PHP_OUTPUT_HANDLER_START);
这样就行,已通过测试
PHP code?12345function callback($buffer) { file_put_contents('你需要的文件名', $buffer); return $buffer; //不需显示页面内容就 return '';}ob_start("callback", PHP_OUTPUT_HANDLER_START);
……
恩 但我改成
function callback($buffer) {
file_put_contents('111.html', $buffer);
return $buffer; //不需显示页面内容就 return '';
}
ob_start("callback");
?>
-
'.$row['xiaofenleiindex'].'
';
require_once('gongxiang.php');
$con = lianjie();
$result = mysql_query("SELECT * FROM tupianwenzi left join detail on tupianwenzi.xiaofenleiindex = detail.xiaofenleidetail");
while($row = mysql_fetch_array($result))
{
echo'
}
?>
mysql_close($con);
?>
又不行了
生成不了 生成不了 生成不了
function callback($buffer) {
file_put_contents('111.html', $buffer);
return $buffer; //不需显示页面内容就 return '';
}
ob_start("callback" , PHP_OUTPUT_HANDLER_START);
要说几遍才能注意到细节呢?
function callback($buffer) {
file_put_contents('111.html', $buffer);
return $buffer; //不需显示页面内容就 return '';
}
ob_start("callback", PHP_OUTPUT_HANDLER_START);
要说几遍才能注意到细节呢?
……
function callback($buffer) {
file_put_contents('111.html', $buffer);
return $buffer; //不需显示页面内容就 return '';
}
ob_start("callback",PHP_OUTPUT_HANDLER_START);
?>
-
'.$row['xiaofenleiindex'].'
';
require_once('gongxiang.php');
$con = lianjie();
$result = mysql_query("SELECT * FROM tupianwenzi left join detail on tupianwenzi.xiaofenleiindex = detail.xiaofenleidetail");
while($row = mysql_fetch_array($result))
{
echo'
}
?>
mysql_close($con);
?>
刚才又测试了一下,对于多段输出需要写作
define('CACHE_FILE', '111.html');function callback($buffer) { file_put_contents(CACHE_FILE, $buffer, FILE_APPEND); return $buffer; //不需显示页面内容就 return '';}file_put_contents(CACHE_FILE, '');ob_start("callback", PHP_OUTPUT_HANDLER_START);
当然你可用全局变量而不是常量来指定目标文件名
<?php/* Created on [2013-3-22] Author[Newton] Filename[test20.php]*/function callback($buffer) { file_put_contents('111.html', $buffer); return $buffer; //不需显示页面内容就 return '';}ob_start("callback",PHP_OUTPUT_HANDLER_START);?><div class="tpwzzs"><ul><?php//require_once('gongxiang.php');//$con = lianjie();//// $result = mysql_query("SELECT * FROM tupianwenzi left join detail on tupianwenzi.xiaofenleiindex = detail.xiaofenleidetail");//// while($row = mysql_fetch_array($result))// {$row = array('id'=>'id','tupianindex'=>'tupianindex','xiaofenleiindex'=>'xiaofenleiindex','detailindex'=>'detailindex');echo'<li><div class="tp"><a target="_blank" href="2jiyemian/2jiyemian.php?id='.$row['id'].'"><img src="/static/imghw/default1.png" data-src="'.$row['tupianindex'].'" class="lazy" .$row['tupianindex'].'" / alt="怎么生成静态页面" ></a></div><div class="detail">'.$row['xiaofenleiindex'].'</div><div class="detail1"><a target="_blank" href="2jiyemian/2jiyemian.php?id='.$row['id'].'">'.$row['detailindex'].'</a></div><div class="detailanniu"><a target="_blank" href="2jiyemian/2jiyemian.php?id='.$row['id'].'"></a></div></li>';// }?><?php //mysql_close($con); ?></ul></div><?php ob_end_flush(); ?>
<!--源码--><div class="tpwzzs"><ul><li><div class="tp"><a target="_blank" href="2jiyemian/2jiyemian.php?id=id"><img src="/static/imghw/default1.png" data-src="tupianindex" class="lazy" / alt="怎么生成静态页面" ></a></div><div class="detail">xiaofenleiindex</div><div class="detail1"><a target="_blank" href="2jiyemian/2jiyemian.php?id=id">detailindex</a></div><div class="detailanniu"><a target="_blank" href="2jiyemian/2jiyemian.php?id=id"></a></div></li></ul></div>
刚才又测试了一下,对于多段输出需要写作
PHP code?1234567define('CACHE_FILE', '111.html');function callback($buffer) { file_put_contents(CACHE_FILE, $buffer, FILE_APPEND); return $buffer; //不需显示页面内容就 retur……
你太给力了 搞定了 你好人做到底吧 怎么把这个页面的php地址都改成html
刚才又测试了一下,对于多段输出需要写作
PHP code?1234567define('CACHE_FILE', '111.html');function callback($buffer) { file_put_contents(CACHE_FILE, $buffer, FILE_APPEND); return $buffer; //不需显示页面内容就 retur……
怎么把页面的PHP改成html啊
比方说
你在
file_put_contents('111.html', $buffer);
前先执行
$buffer = preg_replace('/(href=.+?)\.php/', '$1.html', $buffer);
不过规则可能没那么简单,你想好了再说
我也是类似问题,至今无解,求大神啊

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