Yii框架 小物件复选框传值问题求教。
我想把页面复选框选中的值传给控制器的某个方法,应该怎么实现啊?需要用小物件吗?ajax、js怎么实现啊?求救啊~少年们
如图所示,我想全选,或者选某些个,然后把value值传个某个方法进行下一步操作。
虽然用小物件可以把值传给控制器,但是只能传给当前方法
那么问题来了
如果我的select()方法是查看所有数据,但是如果我想把查看出来的数据传给其他方法进行操作,怎么传过去呀?
跪下了。
我想到的方法是把值传给当前的方法,然后从这个方法中把接受到的值传给其他方法进行操作。
但是我想应该有方法可以自己选择传到那个方法进行操作的,但是初学者不懂。
回复讨论(解决方案)
不解。你提交action的时候 在后台的actionAction(){}方法里直接获取$a=Yii::app()->request->getPost('name');
$a = array()//取值是个数组。
1
2
这跟你用框架有什么关系??
你用widget也是要先赋值在显示的。先搞清楚你要做什么功能在提问,我从字面了解的意思,你就是提交复选框,后台获取值而已!
不解。你提交action的时候 在后台的actionAction(){}方法里直接获取$a=Yii::app()->request->getPost('name');
$a = array()//取值是个数组。
1
2
这跟你用框架有什么关系??
你用widget也是要先赋值在显示的。先搞清楚你要做什么功能在提问,我从字面了解的意思,你就是提交复选框,后台获取值而已!
我的天啊!我居然犯傻了,我明白怎么做了,感谢你的回答啊!!!

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