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Home Backend Development PHP Tutorial 我这个代码点击提交后的为什么页面显示不存在?

我这个代码点击提交后的为什么页面显示不存在?

Jun 20, 2016 pm 12:42 PM
Why does the page show that it does not exist after I click submit with this code?

这是两个页面  下面是1.php  提交后跳转到2.php 再跳转到1.php  我用360的浏览器提交后直接显示页面不存在  是怎么回事? 数据库也没有任何东西    我是新手 可能有很多错误 大家帮我看看吧  谢谢  
     
 
这是1.php  
$db = new PDO('mysql:host=localhost;dbname=t1', 'root', '',array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES 'utf8'"));  
 $rs = $db -> prepare("select * from `baidu`;");  
 $rs -> execute();  
 $list = $rs -> fetchAll(PDO::FETCH_ASSOC);  
?>  
 
 
 
 

 
   foreach($list as $v){
echo $v['type'].'
';  
      echo $v['name'].'
';  
      echo $v['num'].'
';  
      echo $v['site'].'
';  
      echo $v['content'].'
';  
    }  
  ?>  
 
 
      
 
          
 
              
              
              
              
          
 
          
 
            
      
 
 
 
 
 
这是2.php  
$pdo=new PDO("mysql:host=localhost;dbname=t1","root","");
if($pdo->exec("INSERT INTO baidu(  
type,  
name,  
num,  
site,  
content  
)  
VALUES (  
'select','name','num','site','content'  
)")){  
echo "<script>alert('发布成功');location='1.php';</script>";  
}  
?>

回复讨论(解决方案)

看看地址栏上的网址是什么?  
还有,你的站点目录结果及这两个文件所在的位置是怎么样的?


看看地址栏上的网址是什么?  
还有,你的站点目录结果及这两个文件所在的位置是怎么样的?


都在www目录下 没有问题  网址也是http://localhost/2.php    
 


看看地址栏上的网址是什么?  
还有,你的站点目录结果及这两个文件所在的位置是怎么样的?


 
我单独打开2.php也显示不错在  怎么回事


看看地址栏上的网址是什么?  
还有,你的站点目录结果及这两个文件所在的位置是怎么样的?


 
我刚才粗心把那个2.php的文件放到外面了 所以不显示  现在我放到www目录下了  但是数据提交成功后显示不出来刚才提交的内容呢   
而且为什么数据库里面不是插入的数据呢  都是name的值呢  




看看地址栏上的网址是什么?    
还有,你的站点目录结果及这两个文件所在的位置是怎么样的?


 
我刚才粗心把那个2.php的文件放到外面了 所以不显示  现在我放到www目录下了  但是数据提交成功后显示不出来刚才提交的内容呢   
而且为什么数据库里面不是插入的数据呢  都是name的值呢  

因为你2.php的sql没有加$  写的是常量

$pdo=new PDO("mysql:host=localhost;dbname=t1","root","");  
if($pdo->exec("INSERT INTO baidu(  
type,  
name,  
num,  
site,  
content  
)  
VALUES (  
'select','name','num','site','content'  
)")){  
echo "<script>alert('发布成功');location='1.php';</script>";  
}  
 
你自己插入的就是字符串,当然就是那个结果。你并没有获取表单提交过来的值。

post的值没有传过去  我改成(  
'$_POST[select]','$_POST[name]','$_POST[num]','$_POST[site]','$_POST[content]'  
)")  怎么还是不行啊  
 

$pdo=new PDO("mysql:host=localhost;dbname=t1","root","");  
if($pdo->exec("INSERT INTO baidu(  
type,  
name,  
num,  
site,  
content  
)  
VALUES (  
'select','name','num','site','content'  
)")){  
echo "<script>alert('发布成功');location='1.php';</script>";  
}  
 
你自己插入的就是字符串,当然就是那个结果。你并没有获取表单提交过来的值。


 
post的值没有传过去  我改成(  
'$_POST[select]','$_POST[name]','$_POST[num]','$_POST[site]','$_POST[content]'  
)")  怎么还是不行啊  

改成这样了    插入的内容还是原来的那些  
   
('$_POST[select]','$_POST[name]','$_POST[num]','$_POST[site]','$_POST[content]')") 

在2.php 中 print_r($_POST); 看看结果。  
 
改成下面这样试试看  

(&#39;{$_POST[&#39;select&#39;]}&#39;,&#39;{$_POST[&#39;name&#39;]}&#39;,&#39;{$_POST[&#39;num&#39;]}&#39;,&#39;{$_POST[&#39;site&#39;]}&#39;,&#39;{$_POST[&#39;content&#39;]}&#39;)")
Copy after login
Copy after login
Copy after login
Copy after login


在2.php 中 print_r($_POST); 看看结果。

改成下面这样试试看

(&#39;{$_POST[&#39;select&#39;]}&#39;,&#39;{$_POST[&#39;name&#39;]}&#39;,&#39;{$_POST[&#39;num&#39;]}&#39;,&#39;{$_POST[&#39;site&#39;]}&#39;,&#39;{$_POST[&#39;content&#39;]}&#39;)")
Copy after login
Copy after login
Copy after login
Copy after login



改成你这样了 还是不行 print_r($_POST);这句话加在echo前面吗 试了一下 什么都没有 我把echo注释掉 只写这一句 怎么还是弹出来提交成功 然后还和原来一样

你这个SQL写法都有问题的。
老老实实拼接SQL语句字符串吧。




在2.php 中 print_r($_POST); 看看结果。

改成下面这样试试看

(&#39;{$_POST[&#39;select&#39;]}&#39;,&#39;{$_POST[&#39;name&#39;]}&#39;,&#39;{$_POST[&#39;num&#39;]}&#39;,&#39;{$_POST[&#39;site&#39;]}&#39;,&#39;{$_POST[&#39;content&#39;]}&#39;)")
Copy after login
Copy after login
Copy after login
Copy after login



改成你这样了 还是不行 print_r($_POST);这句话加在echo前面吗 试了一下 什么都没有 我把echo注释掉 只写这一句 怎么还是弹出来提交成功 然后还和原来一样
加在首行先看下有不有值。
print_r($_POST);
exit();
$pdo=new PDO("mysql:host=localhost;dbname=t1","root","");
.....





在2.php 中 print_r($_POST); 看看结果。

改成下面这样试试看

(&#39;{$_POST[&#39;select&#39;]}&#39;,&#39;{$_POST[&#39;name&#39;]}&#39;,&#39;{$_POST[&#39;num&#39;]}&#39;,&#39;{$_POST[&#39;site&#39;]}&#39;,&#39;{$_POST[&#39;content&#39;]}&#39;)")
Copy after login
Copy after login
Copy after login
Copy after login

  


   
改成你这样了 还是不行  print_r($_POST);这句话加在echo前面吗  试了一下 什么都没有 我把echo注释掉 只写这一句 怎么还是弹出来提交成功 然后还和原来一样
加在首行先看下有不有值。  
print_r($_POST);  
exit();  
$pdo=new PDO("mysql:host=localhost;dbname=t1","root","");  
.....  

 
我刚下班 试了一下 还是 不行 和原来一样

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