不能修改表 'content' 的设计。它在只读数据库中,该怎么处理
不能修改表 'content' 的设计。它在只读数据库中
$db=$_SERVER['DOCUMENT_ROOT']."\myfirst.mdb";
$connstr="Driver={Microsoft Access Driver (*.mdb)};Dbq=$db";
$connid=odbc_connect($connstr,"","",SQL_CUR_USE_ODBC) or die("数据库打开失败!请联系管理员");
echo 123;
$sql="create table content(id counter constraint primarykey primary key,[标题] varchar(50) null,[省市] varchar(30) null,[内容] varchar(255),[已采] bit,[已发] bit)";
echo $sql;
odbc_exec($connid,$sql);
执行结果:
Warning: odbc_exec() [function.odbc-exec]: SQL error: [Microsoft][ODBC Microsoft Access Driver] 不能修改表 'content' 的设计。它在只读数据库中。, SQL state 42000 in SQLExecDirect in G:\zhengli\access.php on line 9
怎么解决错误,顺利创建access表
------解决方案--------------------
表 content 已经存在了,你再 create table content ... 当然是要报错啦
修改表结构要用 ALTER 指令
你一定要重新建表的话,请先删除该表(DROP 指令)
------解决方案--------------------
没有content表? 权限不够吧。
------解决方案--------------------
在 Access 管理其中新建一空数据库 db1
执行你的代码
$db = realpath("db1.mdb");<br />$connstr = "Driver={Microsoft Access Driver (*.mdb)};Dbq=$db";<br />$connid = odbc_connect($connstr,"","",SQL_CUR_USE_ODBC) or die("数据库打开失败!请联系管理员"); <br />echo 123;<br />$sql = "create table content(id counter constraint primarykey primary key,[标题] varchar(50) null,[省市] varchar(30) null,[内容] varchar(255),[已采] bit,[已发] bit)"; <br />echo $sql;<br />odbc_exec($connid, $sql);
然后用 access 管理器打开它:

结论我想你已经得到了

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