Home Backend Development PHP Tutorial php 得到下周,本周,下月,本月,本季度,下季度

php 得到下周,本周,下月,本月,本季度,下季度

Jun 13, 2016 am 10:39 AM
date echo mktime strtotime

php 得到上周,本周,上月,本月,本季度,上季度

出处:http://hudeyong926.iteye.com/blog/729193


<?phpecho date("Ymd",strtotime("now")), "\n";echo date("Ymd",strtotime("-1 week Monday")), "\n";echo date("Ymd",strtotime("-1 week Sunday")), "\n";echo date("Ymd",strtotime("+0 week Monday")), "\n";echo date("Ymd",strtotime("+0 week Sunday")), "\n";echo "*********第几个月:";echo date('n'); echo "*********本周周几:";echo date("w"); echo "*********本月天数:";echo date("t");echo "*********";echo '<br>上周:<br>';echo date("Y-m-d H:i:s",mktime(0, 0 , 0,date("m"),date("d")-date("w")+1-7,date("Y"))),"\n";echo date("Y-m-d H:i:s",mktime(23,59,59,date("m"),date("d")-date("w")+7-7,date("Y"))),"\n";echo '<br>本周:<br>';echo date("Y-m-d H:i:s",mktime(0, 0 , 0,date("m"),date("d")-date("w")+1,date("Y"))),"\n";echo date("Y-m-d H:i:s",mktime(23,59,59,date("m"),date("d")-date("w")+7,date("Y"))),"\n";echo '<br>上月:<br>';echo date("Y-m-d H:i:s",mktime(0, 0 , 0,date("m")-1,1,date("Y"))),"\n";echo date("Y-m-d H:i:s",mktime(23,59,59,date("m") ,0,date("Y"))),"\n";echo '<br>本月:<br>';echo date("Y-m-d H:i:s",mktime(0, 0 , 0,date("m"),1,date("Y"))),"\n";echo date("Y-m-d H:i:s",mktime(23,59,59,date("m"),date("t"),date("Y"))),"\n"; $season = ceil((date('n'))/3);//当月是第几季度echo '<br>本季度:<br>';echo date('Y-m-d H:i:s', mktime(0, 0, 0,$season*3-3+1,1,date('Y'))),"\n";echo date('Y-m-d H:i:s', mktime(23,59,59,$season*3,date('t',mktime(0, 0 , 0,$season*3,1,date("Y"))),date('Y'))),"\n"; $season = ceil((date('n'))/3)-1;//上季度是第几季度echo '<br>上季度:<br>';echo date('Y-m-d H:i:s', mktime(0, 0, 0,$season*3-3+1,1,date('Y'))),"\n";echo date('Y-m-d H:i:s', mktime(23,59,59,$season*3,date('t',mktime(0, 0 , 0,$season*3,1,date("Y"))),date('Y'))),"\n"; ?> php两个日期相减得天数<?phpfunction count_days($a,$b){ $a_dt=getdate($a); $b_dt=getdate($b); $a_new=mktime(12,0,0,$a_dt['mon'],$a_dt['mday'],$a_dt['year']); $b_new=mktime(12,0,0,$b_dt['mon'],$b_dt['mday'],$b_dt['year']); return round(abs($a_new-$b_new)/3600/24);}    function count_days($formdate,$todate){        return round(abs(strtotime($formdate)-strtotime($todate))/3600/24);    }
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