Home Backend Development PHP Tutorial 一段逻辑判断,实现不了目的

一段逻辑判断,实现不了目的

Jun 13, 2016 am 10:35 AM
class news php title

一段逻辑判断,实现不了目的,求助
想只用一个页面,显示新闻系统的三种功能:"index.php?news_title=xxx?news_class=xxx",需要达到以下目的:

1,当news_title和news_class元素均为空或者都有值时,该页面显示全部新闻的标题列表;

2,当news_title和news_class两个元素中,一个有值另一个无值时,该页面显示元素有值的内容。

------算法逻辑和代码实现:

PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->//首先,取得浏览器的传值:news_title和news_classif(isset($_GET['news_class'])){  $news_class=$_GET['news_class'];}else{  $news_class='';} if(isset($_GET['news_title'])){  $news_title=$_GET['news_title'];}else{  $news_title='';}//然后开始判断,准备显示有关的内容if ($news_title='')//当news_title元素为空时,开始判断news_class元素是否为空{   if ($news_class='')//news_class也为空,则该页面显示所有news表的news_title列表    {      $sql="SELECT news_title,in_time FROM news";      $result = mysql_query($sql);       while ($row=mysql_fetch_assoc($result))             {?>                     <tr>          <td>        <?php echo $row['news_title']; ?>        <?php echo $row['in_time']; ?>      </td>        </tr><?php }mysql_free_result($result);    }    else//当news_class不为空,则该页面显示news_class的相关内容    {      $sql="SELECT * FROM news where news_class='$news_class'";      $result = mysql_query($sql);       while ($row=mysql_fetch_assoc($result))             {?>                     <tr>          <td>
<?php echo $row['news_title']; ?>              <?php echo $row['in_time']; ?>          </td>        </tr><?php }mysql_free_result($result);    }}else  //当news_title不为空值时,开始判断news_class是否为空{   if ($news_class='')//news_class为空,则该页面show出news_title的相关数据    {      $sql="SELECT * FROM news where news_title='$news_title'";      $result = mysql_query($sql);       while ($row=mysql_fetch_assoc($result))             {?>                     <tr>          <td> <?php echo $row['news_title']; ?>               Author : <?php echo $row['news_author']; ?>                Date : <?php echo $row['in_time']; ?>                       <?php echo $row['news_content']; ?>      </td>        </tr><?php }mysql_free_result($result);          }    else//当news_class也不为空值时,则该页面显示所有news表的数据(和两者都为空时一样)    {      $sql="SELECT news_title,in_time FROM news";      $result = mysql_query($sql);       while ($row=mysql_fetch_assoc($result))             {?>                     <tr>          <td>
<?php echo $row['news_title']; ?>          <?php echo $row['in_time']; ?>      </td>        </tr><?php }mysql_free_result($result);          }}
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以上代码在最终显示时,全部显示为新闻的标题列表了,即:new_title列表。

敢问各位大虾,我这逻辑错了,还是写法有问题?


------解决方案--------------------
你这样写不太好呢。

你请求数据与逻辑与表现的html代码都搞在一起,
最好是先逻辑判断好。再去请求数据。最后一个foreach出html。

看你代码很吃力不如从新写了。=_=zzz
------解决方案--------------------
index.php?news_title=xxx?news_class=xxx
中的参数串,不是常规的格式
常规的是 index.php?news_title=xxx&news_class=xxx

你个到的是 array( 'news_title' => 'xxx?news_class=xxx')
需加工后方可使用 

------解决方案--------------------
PHP code
if ($a && $b) {    // 显示全部} elseif ($a) {    ;} elseif ($b) {    ;}<br><font color="#e78608">------解决方案--------------------</font><br>url 要写作 index.php?news_title=xxx&news_class=xxx<br><br>$news_title = $news_class = '';<br>if(isset($_GET['news_title'])) $news_title = $_GET['news_title'];<br>if(isset($_GET['news_class'])) $news_class = $_GET['news_class'];<br><br>if($news_title != '' && $news_class != '') {<br> //两个都有<div class="clear">
                 
              
              
        
            </div>
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