How to efficiently parse indented paths and optimize JavaScript code?

Improve JavaScript code efficiency: Optimize indented path analysis

This article aims to optimize a piece of JavaScript code to extract path-level information more efficiently from strings containing indents. The original code is functioning normally, but the readability, simplicity and exception handling capabilities need to be improved.

The original code calculates the number of spaces to determine the indentation level, and then builds the path. This method is logically complex and has poor maintenance when dealing with irregular indentation or blank lines.

The optimized code adopts a clearer strategy: first, split the input string by line, and use map function to convert each line into an object with two attributes: level (level) and value (text content). The level calculation is efficiently obtained by dividing the number of spaces in the first row by 4 and rounding it down (using the ~~ operator).

The key to optimizing code is to deal with hierarchical jumps: the original code is logically cumbersome in this link. The optimization code uses the reduce function to traverse the line data and check whether the difference between the current line level and the previous line level is greater than 1. If so, correct the current line level to the previous line level to add 1, thereby effectively dealing with irregular indentation and avoiding logical vulnerabilities in the original code.

The code uses path array to store the various hierarchical elements of the current path, and result array stores the final path results. Iterate through the processed line data, update the path array according to the hierarchy of each line, and build a path string to add it to result array. This method makes the code logic clear and easy to understand and maintain.

Finally, the optimized code improves the readability and maintainability of the code through concise data structure and clear logic, solves the potential problems of the original code, and maintains the same output results.

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