C language programming to find the reciprocal of 1 to n

The sum of the inverses of 1 to n can be obtained by looping through each number from 1 to n, calculating its inverses and accumulating them. Code: Get the n value entered by the user. Iterate using a for loop for each number from 1 to n. Calculate the reciprocity (1.0/i) of each number and add it to the accumulator sum. Finally, print out the reciprocal sum of 1 to n.

C language programming to find the reciprocal of 1 to n

Calculating the inverse sum of 1 to n is a common programming problem.

method:

We can use a loop to iterate over each number from 1 to n and calculate its reciprocal. Then, we accumulate these countdowns to get the final result.

Code:

 <code class="c">#include <stdio.h> int main() { int n, i; float sum = 0; printf("请输入n: "); scanf("%d", &n); for (i = 1; i </stdio.h></code>

explain:

• First, we get the n value entered by the user.
• We then iterate using a for loop from 1 to n.
• In each iteration, we calculate the reciprocal of each number (1.0/i) and add it to the accumulator sum.
• Finally, we print out the reciprocal sum of 1 to n.

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