Minimum Length of String After Operations
3223. Minimum Length of String After Operations
Difficulty: Medium
Topics: Hash Table, String, Counting
You are given a string s.
You can perform the following process on s any number of times:
- Choose an index i in the string such that there is at least one character to the left of index i that is equal to s[i], and at least one character to the right that is also equal to s[i].
- Delete the closest character to the left of index i that is equal to s[i].
- Delete the closest character to the right of index i that is equal to s[i].
Return the minimum length of the final string s that you can achieve.
Example 1:
- Input: s = "abaacbcbb"
- Output: 5
-
Explanation: We do the following operations:
- Choose index 2, then remove the characters at indices 0 and 3. The resulting string is s = "bacbcbb".
- Choose index 3, then remove the characters at indices 0 and 5. The resulting string is s = "acbcb".
Example 2:
- Input: s = "aa"
- Output: 2
- Explanation: We cannot perform any operations, so we return the length of the original string.
Constraints:
- 1 <= s.length <= 2 * 105
- s consists only of lowercase English letters.
Hint:
- Only the frequency of each character matters in finding the final answer.
- If a character occurs less than 3 times, we cannot perform any process with it.
- Suppose there is a character that occurs at least 3 times in the string, we can repeatedly delete two of these characters until there are at most 2 occurrences left of it.
Solution:
We need to focus on the frequency of each character in the string. Here’s the approach to solve it:
Approach:
-
Count Character Frequencies:
- Use a frequency table to count how many times each character appears in the string.
-
Reduce Characters with Frequency >= 3:
- If a character appears 3 or more times, we can repeatedly delete two of them until only 2 occurrences are left.
-
Calculate the Minimum Length:
- Sum up the remaining counts of all characters after reducing the frequencies.
-
Frequency Count:
- Iterate through the string, and for each character, increment its count in the $frequency array.
-
Reduction of Characters:
- For each character in the $frequency array, check if its count is 3 or more. If so, reduce it to at most 2.
-
Calculate the Result:
- Sum the values in the $frequency array to get the minimum possible length of the string.
- Input: s = "abaacbcbb"
- Frequencies: ['a' => 3, 'b' => 4, 'c' => 2]
- After reduction:
- 'a' => 2 (reduced from 3),
- 'b' => 2 (reduced from 4),
- 'c' => 2 (no reduction needed).
- Minimum length: 2 2 2 = 6.
- Input: s = "aa"
- Frequencies: ['a' => 2]
- No reduction needed since no character has a frequency of 3 or more.
- Minimum length: 2.
-
Time Complexity:
- Counting frequencies: O(n), where n is the length of the string.
- Reduction: O(1) (constant time, as there are only 26 lowercase letters).
- Summing frequencies: O(1).
- Overall: O(n).
-
Space Complexity:
- O(1), since the frequency array has at most 26 entries.
- GitHub
Let's implement this solution in PHP: 3223. Minimum Length of String After Operations
<?php /** * @param String $s * @return Integer */ function minimumLength($s) { ... ... ... /** * go to ./solution.php */ } // Example 1 $s1 = "abaacbcbb"; echo "Input: $s1\n"; echo "Output: " . minimumLength($s1) . "\n"; // Example 2 $s2 = "aa"; echo "Input: $s2\n"; echo "Output: " . minimumLength($s2) . "\n"; ?>
Explanation:
Example Walkthrough:
Example 1:
Example 2:
Complexity:
This solution is efficient and works well within the problem's constraints.
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