


How Can I Combine Multiple SELECT Statements to Analyze Task Completion and Lateness?
Efficient Data Analysis: Combining Multiple SELECT Statements
Database queries often require combining data from multiple sources or applying several transformations. Joining the outputs of multiple SELECT
statements offers a powerful way to manipulate data and gain valuable insights.
Consider a task database where each record represents a task, including a deadline (PALT) and the task's age (days since start). A task is late if its age surpasses its PALT. Our goal is to generate a summary table showing each person's total task count and the number of overdue tasks.
This can be achieved using two separate SELECT
statements:
SELECT ks, COUNT(*) AS '# Tasks' FROM Table GROUP BY ks;
This query counts the total tasks for each person (identified by ks
).
SELECT ks, COUNT(*) AS '# Late' FROM Table WHERE Age > Palt GROUP BY ks;
This query counts the number of late tasks for each person.
To combine these, we use a LEFT JOIN
:
SELECT t1.ks, t1.'# Tasks', COALESCE(t2.'# Late', 0) AS '# Late' FROM (SELECT ks, COUNT(*) AS '# Tasks' FROM Table GROUP BY ks) t1 LEFT JOIN (SELECT ks, COUNT(*) AS '# Late' FROM Table WHERE Age > Palt GROUP BY ks) t2 ON t1.ks = t2.ks;
This joins the results based on the ks
column. COALESCE
handles cases where a person has no late tasks, replacing NULL
with 0.
The final table shows ks
(person ID), # Tasks
(total tasks), and # Late
(number of late tasks, or 0 if none). This enables a thorough analysis of individual workloads and the percentage of overdue tasks.
The above is the detailed content of How Can I Combine Multiple SELECT Statements to Analyze Task Completion and Lateness?. For more information, please follow other related articles on the PHP Chinese website!

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