String Matching in an Array
1408. String Matching in an Array
Difficulty: Easy
Topics: Array, String, String Matching
Given an array of string words, return all strings in words that is a substring of another word. You can return the answer in any order.
A substring is a contiguous sequence of characters within a string
Example 1:
- Input: words = ["mass","as","hero","superhero"]
- Output: ["as","hero"]
- Explanation: "as" is substring of "mass" and "hero" is substring of "superhero". ["hero","as"] is also a valid answer.
Example 2:
- Input: words = ["leetcode","et","code"]
- Output: ["et","code"]
- Explanation: "et", "code" are substring of "leetcode".
Example 3:
- Input: words = ["blue","green","bu"]
- Output: []
- Explanation: No string of words is substring of another string.
Constraints:
- 1 <= words.length <= 100
- 1 <= words[i].length <= 30
- words[i] contains only lowercase English letters.
- All the strings of words are unique.
Hint:
- Bruteforce to find if one string is substring of another or use KMP algorithm.
Solution:
We need to find all strings in the words array that are substrings of another word in the array, you can use a brute force approach. The approach involves checking each string in the list and verifying if it's a substring of any other string.
Let's implement this solution in PHP: 1408. String Matching in an Array
<?php /** * @param String[] $words * @return String[] */ function stringMatching($words) { ... ... ... /** * go to ./solution.php */ } // Example 1 $words = ["mass", "as", "hero", "superhero"]; print_r(stringMatching($words)); // Example 2 $words = ["leetcode", "et", "code"]; print_r(stringMatching($words)); // Example 3 $words = ["blue", "green", "bu"]; print_r(stringMatching($words)); ?> <h3> Explanation: </h3> <ol> <li>The function stringMatching loops through all the words in the input array.</li> <li>For each word, it compares it with every other word in the array using a nested loop.</li> <li>It uses PHP's strpos() function to check if one string is a substring of another. The strpos() function returns false if the substring is not found.</li> <li>If a substring is found, we add the word to the result array and break out of the inner loop, as we only need to record the word once.</li> <li>Finally, the function returns the result array containing all the substrings.</li> </ol> <h3> Time Complexity: </h3> <ul> <li>The time complexity is <em><strong>O(n<sup>2</sup> x m)</strong></em>, where <em><strong>n</strong></em> is the number of words and <em><strong>m</strong></em> is the maximum length of a word. This is because we are performing a substring search for each word within every other word.</li> </ul> <h3> Example Outputs: </h3> <p>For input ["mass", "as", "hero", "superhero"], the output will be:<br> </p> <pre class="brush:php;toolbar:false">Array ( [0] => as [1] => hero )
For input ["leetcode", "et", "code"], the output will be:
Array ( [0] => et [1] => code )
For input ["blue", "green", "bu"], the output will be:
Array ( )
This solution works well for the given problem constraints.
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