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Inheritance in JavaScript: The Constructor Property Puzzle
Home Web Front-end JS Tutorial Why Doesn't JavaScript's Constructor Property Update During Prototypical Inheritance?

Why Doesn't JavaScript's Constructor Property Update During Prototypical Inheritance?

Jan 01, 2025 am 07:22 AM

Why Doesn't JavaScript's Constructor Property Update During Prototypical Inheritance?

Inheritance in JavaScript: The Constructor Property Puzzle

In JavaScript, inheritance refers to the process of creating new objects that inherit properties and methods from existing objects. One aspect of inheritance that often raises questions is the behavior of the constructor property.

Consider the following code:

function a() {}
function b() {}
function c() {}

b.prototype = new a();
c.prototype = new b();

console.log((new a()).constructor); // a()
console.log((new b()).constructor); // a()
console.log((new c()).constructor); // a()
Copy after login

Why isn't the constructor property updated for b and c?

The constructor property of a function instance points to the function itself. In this case, a(), b(), and c() are all function instances, so their constructor property references them. When we set b.prototype and c.prototype to instances of a() and b(), respectively, we are essentially changing the prototype chain of b and c, but not modifying the constructor property.

Am I doing inheritance wrong?

No, you are not necessarily doing inheritance wrong. This behavior is the intended result of prototypical inheritance in JavaScript. Inheritance in JavaScript involves setting the prototype property of the derived class (e.g., b and c) to an instance of the base class (e.g., a) or its prototype object. This does not update the constructor property.

What is the best way to update the constructor property?

One approach to manually update the constructor property is to assign the derived constructor function as the prototype object's constructor property. However, this is not always necessary and may result in constructor confusion for custom object types.

How does the instanceof operator work in this context?

The instanceof operator checks if an object is an instance of a specific constructor function. In this case, even though the constructor property of b and c instances is set to a(), the instanceof operator correctly identifies them as instances of b and c by traversing their prototype chains.

This traversal process matches the internal [[proto]] property of each object in the prototype chain to the prototype property of the constructor function. If a match is found, the instanceof operator returns true; otherwise, it returns false.

Understanding the intricacies of the constructor property and inheritance is crucial for effective JavaScript development. By considering the limitations and implications of prototypical inheritance, you can create well-designed and maintainable code.

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