Home Backend Development Golang Why Doesn't `fmt.Println` Always Call My Custom Type's `String()` Method?

Why Doesn't `fmt.Println` Always Call My Custom Type's `String()` Method?

Dec 31, 2024 am 11:43 AM

Why Doesn't `fmt.Println` Always Call My Custom Type's `String()` Method?

Method Invocation Failure with Interface Conversion in fmt.Println

When attempting to use fmt.Println to print a value of a custom type, the expected method invocation of the type's String() method may not occur. This issue arises when the value is passed as a value rather than a pointer.

Consider the example code:

import "fmt"

type Car struct {
    year int
    make string
}

func (c *Car) String() string {
    return fmt.Sprintf("{make:%s, year:%d}", c.make, c.year)
}

func main() {
    myCar := Car{year: 1996, make: "Toyota"}
    fmt.Println(myCar) // Value-based object
}
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In this instance, the expected String() method of Car will not be called when fmt.Println is used with a value of type Car. Instead, the value will be formatted using the default Go formatting mechanism.

To resolve this issue and ensure that the custom String() method is invoked regardless of whether the object is a value or a pointer, the following options are available:

  • Implement String() on Value-based Types: Although this approach eliminates the need for manual conversion, it incurs a performance penalty due to copying the object each time the String() method is called.
  • Always Pass Pointers to fmt.Println: By passing a pointer to fmt.Println, the Println function will automatically dereference it and invoke the String() method on the underlying value. This ensures that the desired formatting is applied irrespective of whether the object is a value or a pointer:
fmt.Println(&myCar) // Pointer-based object
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By adhering to these guidelines, you can reliably invoke the String() method and control the formatting of custom types within fmt.Println.

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