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Comparing Time Structures: Why Difference vs Equality
Home Backend Development Golang Go's `time.Time`: Why Does `==` Sometimes Fail When Comparing Times?

Go's `time.Time`: Why Does `==` Sometimes Fail When Comparing Times?

Dec 27, 2024 am 02:12 AM

Go's `time.Time`: Why Does `==` Sometimes Fail When Comparing Times?

Comparing Time Structures: Why Difference vs Equality

Time.Time, a struct in Go, houses not only time components (seconds and nanoseconds) but also a location pointer. In comparing struct instances via ==, all fields are subject to examination.

The Go Spec dictates:

Hence, t1 == t2 compares all fields, including the location, which are distinct pointers. This exclusivity is despite both locations representing the same time zone.

As a reminder, the time.Time documentation cautions against using Time values as identifiers in maps or databases without guaranteeing consistent locations. The solution lies in using the UTC or Local methods to ensure identical location pointers.

Alternatively, one can leverage the In() method to establish the desired location pointer, as demonstrated in the GoSpec.

By setting equivalent location pointers, Time structures with identical date and time components will now yield true when compared via ==. The Equal() method, however, will consistently return true regardless of locations.

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