How Can We Optimize Palindrome Checking in Programming?

Optimized Palindrome Check

In programming, a palindrome is a string that reads the same forward and backward. Checking for palindromes is a common task, so it's important to have an efficient implementation.

In the code you provided, you compare characters from both sides of the string towards the middle. However, there's a more direct approach that involves comparing the first and last characters recursively.

The optimized code is as follows:

public static boolean istPalindrom(char[] word) {
    int i1 = 0;
    int i2 = word.length - 1;
    while (i2 > i1) {
        if (word[i1] != word[i2]) {
            return false;
        }
        ++i1;
        --i2;
    }
    return true;
}

Example:

Consider the input string "andna".

• Initially, i1 is 0 and i2 is 4.
• First loop iteration: We compare word[0] and word[4]. They're equal, so i1 becomes 1 and i2 becomes 3.
• Second loop iteration: We compare the second 'n's. They're equal, so i1 becomes 2 and i2 becomes 2.
• Third loop iteration: Now i1 and i2 are equal, so the while loop terminates and we return true because the string is a palindrome.

This approach offers several advantages:

• It's more concise and readable.
• It's faster than comparing characters from the middle out because it avoids unnecessary loop iterations.
• It avoids creating new arrays or modifying existing ones, which can improve performance and reduce memory consumption.

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