Home Backend Development Golang Why Does a Go `for` Loop with a Struct Initializer Cause a Syntax Error?

Why Does a Go `for` Loop with a Struct Initializer Cause a Syntax Error?

Dec 24, 2024 am 01:34 AM

Why Does a Go `for` Loop with a Struct Initializer Cause a Syntax Error?

Struct in for Loop Initializer Syntax Error

In a Go program, using a struct expression as the initializer in a for loop can result in a syntax error at compile time. This error occurs when the opening brace of the struct expression is interpreted ambiguously as the start of the for loop block.

Consider the following code example:

type Request struct {
    id   int
    line []byte
    err  error
}

func main() {
    go func() {
        for r := Request{}; r.err == nil; r.id++ {
            r.line, r.err = input.ReadSlice(0x0a)
            channel <- r
        }
    }()
}
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This code will fail to compile with the error:

expected boolean or range expression, found simple statement (missing parentheses around composite literal?) (and 1 more errors)
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To resolve this ambiguity, you can explicitly specify that the struct expression is a composite literal by enclosing it in parentheses:

func main() {
    go func() {
        for r := (Request{}); r.err == nil; r.id++ {
            r.line, r.err = input.ReadSlice(0x0a)
            channel <- r
        }
    }()
}
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With this modification, the code will compile successfully. The parentheses make it clear that the opening brace is part of a composite literal, not the for loop itself.

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