How Can I Verify Interface Implementation in Go at Compile Time?

Using Type Assertions to Verify Interface Implementation

When working with interfaces, it's essential to understand how to check if a value implements a specific interface at runtime. This can be particularly useful in scenarios where the type of the value is unknown or dynamic.

To achieve this, you can utilize the type assertion syntax introduced in Go. In your example, you correctly tried to use the syntax _, ok := val.(Somether) to check if the MyType value val implements the Somether interface. However, this approach only works if the value is already of an interface type.

To check a specific type, you can use the following syntax:

var _ Somether = (*MyType)(nil)

In this expression, _ is a blank identifier used to disregard the named variable and focus on the type assertion itself. The *MyType expression creates a pointer to the MyType value, and (nil) assigns a nil value to this pointer. This effectively checks if *MyType implements the Somether interface. If it does, the code compiles without errors; otherwise, it produces a compile-time error indicating that MyType lacks the required Method method implementation.

This technique allows you to explicitly verify whether a given type implements a particular interface without the need for reflection.

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