Table of Contents
Sorting Structs with Multiple Sort Parameters
Using slices.SortFunc for Concise Sorting
Leveraging sort.Slice for Simpler Sorting
Utilizing sort.Sort for More Flexibility
Choosing the Right Approach
Home Backend Development Golang How to Sort Structs in Go by Multiple Parameters (LastName then FirstName)?

How to Sort Structs in Go by Multiple Parameters (LastName then FirstName)?

Dec 16, 2024 pm 05:34 PM

How to Sort Structs in Go by Multiple Parameters (LastName then FirstName)?

Sorting Structs with Multiple Sort Parameters

When working with arrays or slices of structs, sorting them by multiple parameters can be a common requirement. This guide explores different approaches to sorting structs based on multiple parameters, focusing on the specific need of sorting by both LastName and FirstName.

Using slices.SortFunc for Concise Sorting

In Go 1.22 and later, the slices.SortFunc function offers a concise and readable solution for sorting slices. It takes a custom comparison function as an argument, allowing you to define the sort criteria. For sorting by LastName and then FirstName, you can use the cmp.Or and cmp.Compare functions:

slices.SortFunc(members, func(a, b Member) int {
    return cmp.Or(
        cmp.Compare(a.LastName, b.LastName),
        cmp.Compare(a.FirstName, b.FirstName),
    )
})
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Leveraging sort.Slice for Simpler Sorting

The sort.Slice function provides a straightforward way to sort slices. It takes a slice and a comparison function as arguments. The comparison function should return true if its first argument is less than its second argument, and false otherwise. To sort by LastName and then FirstName, you can create the following comparison function:

sort.Slice(members, func(i, j int) bool {
    if members[i].LastName != members[j].LastName {
        return members[i].LastName < members[j].LastName
    }
    return members[i].FirstName < members[j].FirstName
})
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Utilizing sort.Sort for More Flexibility

Another approach is to use the sort.Sort function, which takes a value that implements the sort.Interface interface. This interface requires three methods: Len(), Swap(), and Less(). The Less() method is the same as the comparison function used in the previous approaches.

type byLastFirst []Member

func (members byLastFirst) Len() int           { return len(members) }
func (members byLastFirst) Swap(i, j int)      { members[i], members[j] = members[j], members[i] }
func (members byLastFirst) Less(i, j int) bool {
    if members[i].LastName != members[j].LastName {
        return members[i].LastName < members[j].LastName
    }
    return members[i].FirstName < members[j].FirstName
}

sort.Sort(byLastFirst(members))
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Choosing the Right Approach

Which approach is best depends on your specific application and performance requirements. Unless performance is a critical factor, choosing the most convenient approach based on readability and maintenance is recommended.

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