How to Omit Empty Nested Structs in Go's JSON Marshaling?
Omitting Empty Nested Stucts in JSON Marshaling
Context:
JSON marshaling in Go enables converting structs into JSON objects. By default, all exported struct fields are included in the JSON output. However, empty fields can be omitted by specifying :",omitempty" as the field tag.
Problem:
If a nested struct is empty (i.e., has zero values for all its fields), it may still appear in the JSON output even though it has the :",omitempty" tag.
Solution:
To omit empty nested structs, it is necessary to use pointers to the structs. By doing so, the empty value of the nested struct will be considered a nil pointer.
Explanation:
From the Go documentation:
- Struct values encode as JSON objects. Empty values include nil pointers.
- The omitempty tag applies to empty values, including nil pointers.
Therefore, by using a pointer to the nested struct, we ensure that it is considered an empty value and thus omitted from the JSON output when the :",omitempty" tag is used.
Example:
type ColorGroup struct { ID int `json:",omitempty"` Name string Colors []string } type Total struct { A *ColorGroup `json:",omitempty"` B string `json:",omitempty"` } // Empty nested struct (zero values) group := Total{ B: "abc", } // Marshal group without nested struct (only "B" field included) b, err := json.Marshal(group) if err != nil { fmt.Println("error:", err) } os.Stderr.Write(b)
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