How to Filter an Array of Objects Based on IDs from Another Array?

Targeting Specific Objects in an Array

Filtering an array of objects based on a different array can be useful in various scenarios. Consider a scenario where we have an array of people objects and an additional array containing specific identifiers (e.g., IDs).

Given an array of people:

const people = [
  { id: "1", name: "abc", gender: "m", age: "15" },
  { id: "2", name: "a", gender: "m", age: "25" },
  { id: "3", name: "efg", gender: "f", age: "5" },
  { id: "4", name: "hjk", gender: "m", age: "35" },
  { id: "5", name: "ikly", gender: "m", age: "41" },
  { id: "6", name: "ert", gender: "f", age: "30" },
  { id: "7", name: "qwe", gender: "f", age: "31" },
  { id: "8", name: "bdd", gender: "m", age: "78" }
];

and an array of desired IDs:

const id_filter = [1, 4, 5, 8];

Filtering Objects Using Array.filter

To filter the array of people based on the provided IDs, we can employ the array's filter() method. This method accepts a callback function that receives each element of the array and returns a Boolean value. To cater to our filtering needs, we define our callback function as follows:

person => id_filter.includes(person.id)

This callback function essentially checks whether the current person's ID is present in the id_filter array. If found, it returns true; otherwise, it returns false.

Utilizing this callback function, we can now filter our array of people:

const filteredPeople = people.filter(person => id_filter.includes(person.id));

The resulting filteredPeople array will contain only those objects from the original array whose IDs match the values in id_filter.

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