How Can I Sort a Go Map by Its Integer Values in Descending Order?

Sorting Map Values in Go

In Go, a given map where keys are of type string and values are of type int can be sorted based on its values in descending order.

Problem Statement:

Consider the following map:

map[string]int{"hello": 10, "foo": 20, "bar": 20}

The goal is to print the sorted key-value pairs as:

foo, 20
bar, 20
hello, 10

Implementation:

To achieve this sorting, an implementation of the Go sort interface is necessary. This is done by defining the Len(), Less(), and Swap() functions:

func rankByWordCount(wordFrequencies map[string]int) PairList {
  pl := make(PairList, len(wordFrequencies))
  i := 0
  for k, v := range wordFrequencies {
    pl[i] = Pair{k, v}
    i++
  }
  sort.Sort(sort.Reverse(pl))
  return pl
}

type Pair struct {
  Key string
  Value int
}

type PairList []Pair

func (p PairList) Len() int { return len(p) }
func (p PairList) Less(i, j int) bool { return p[i].Value < p[j].Value }
func (p PairList) Swap(i, j int){ p[i], p[j] = p[j], p[i] }

Conclusion:

By implementing the sort interface and leveraging the sort.Reverse function, maps can be effectively sorted by their values in Go, enabling various sorting scenarios.

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