Can C Functions Be Overloaded Based on Their Return Type?
Overloading Functions by Return Type in C
While C supports function overloading based on parameter types, it also offers the intriguing possibility of selecting different function implementations based on the return value. This can be a valuable technique for handling cases where the same input can produce different desired outputs.
Explicit Differentiation by Casting
In the presented use case, we have a function mul that should return an integer when assigned to an integer variable and a string when assigned to a string variable. However, C requires explicit differentiation to achieve this:
std::string s = mul(54, 3); // Proper conversion
Dummy Pointer Differentiation
An alternative approach involves adding dummy parameters to the function signatures. By passing NULL pointers of the desired return types, we can force the compiler to select the appropriate function:
int mul(int* dummy, int i, int j) { return i*j; } std::string mul(std::string* dummy, char c, int n) { return std::string(n, c); } int n = mul(NULL, 6, 3); // Return integer std::string s = mul(NULL, 54, 3); // Return string
Template-Based Return Value Differentiation
C templates provide another method for return value overloading. We can create a "dummy" function with code that won't compile unless instantiated with specific templates:
template<typename T> T mul(int i, int j) { const int k = 25 ; k = 36 ; } template<> int mul<int>(int i, int j) { return i * j ; } template<> std::string mul<std::string>(int i, int j) { return std::string(j, static_cast<char>(i)) ; }
Template Differentiation with Different Parameters
If necessary, template-based overloading can also support different parameter types for different return value specializations:
template<typename T> T mul(int i, int j) {...} template<> int mul<int>(int i, int j) {...} template<> std::string mul<std::string>(char i, int j) {...}
By utilizing these techniques, programmers can create functions that provide different outputs based on the expected return value type.
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