Home Backend Development C++ Does the C Standard Guarantee the Size and Memory Layout of `std::array`?

Does the C Standard Guarantee the Size and Memory Layout of `std::array`?

Nov 24, 2024 am 10:49 AM

Does the C   Standard Guarantee the Size and Memory Layout of `std::array`?

Is the Size of std::array Enforced by the Standard?

In C 11, std::array is guaranteed to have contiguous storage and a performance that surpasses or equals a regular array. However, the question remains: does the standard explicitly define the size and memory layout of std::array?

Exploring the Standard's Requirements

The standard defines std::array as an aggregate that can be initialized using the syntax:

std::array<T, N> a = { initializer-list };
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As an aggregate, std::array cannot employ constructors to convert data from the initializer list. This implies that the array primarily stores the values themselves.

Possible Deviations from Expected Behavior

Technically, the standard does not prohibit certain potential deviations:

  • Auxiliary Data Storage: std::array could reserve additional memory beyond the specified values, allowing for error detection if data is written past the array's bounds.
  • Alignment Differences: Compilers might apply distinct alignment or padding to std::arrays compared to built-in arrays, particularly for supporting advanced alignment requirements.

Compiler Variations

Despite the standard's ambiguity, practical usage in major compilers like GNU and Intel suggests that std::array's size and memory layout mirror those of regular arrays.

std::vector< std::array<int, N> > x(M);
typedef int (*ArrayPointer)[N];
ArrayPointer y = (ArrayPointer) &x[0][0];
// Safe multidimensional array-like usage
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It's crucial to note that while this code functions as expected, it's not a guarantee that all implementations will follow this pattern. Therefore, relying on this behavior is not advisable in mission-critical code.

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