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Parsing Non-Standard Time Formats in JSON
Home Backend Development Golang How to Handle Non-Standard Time Formats in JSON Parsing?

How to Handle Non-Standard Time Formats in JSON Parsing?

Nov 09, 2024 am 05:03 AM

How to Handle Non-Standard Time Formats in JSON Parsing?

Parsing Non-Standard Time Formats in JSON

In typical JSON parsing scenarios, time values are expected to adhere to the RFC 3339 format ("2006-01-02T15:04:05Z07:00"). However, when dealing with non-standard time formats, the default JSON decoder encounters issues.

To overcome this, one can implement custom marshal and unmarshal methods for a custom data type that represents the non-standard time format. For instance:

// Create a type alias for the non-standard time format
type JsonBirthDate time.Time

// Implement UnmarshalJSON to handle conversion from JSON string to time.Time
func (j *JsonBirthDate) UnmarshalJSON(b []byte) error {
    s := strings.Trim(string(b), "\"")
    t, err := time.Parse("2006-01-02", s)
    if err != nil {
        return err
    }
    *j = JsonBirthDate(t)
    return nil
}

// Implement MarshalJSON to handle conversion from time.Time to JSON string
func (j JsonBirthDate) MarshalJSON() ([]byte, error) {
    return json.Marshal(time.Time(j))
}
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Now, incorporate this custom type into the Person struct:

type Person struct {
    Name string `json:"name"`
    BirthDate JsonBirthDate `json:"birth_date"`
}
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By utilizing these custom methods, the JSON decoder can now successfully parse the non-standard time format:

person := Person{}
decoder := json.NewDecoder(req.Body)
if err := decoder.Decode(&person); err != nil {
    log.Println(err)
}
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