Home Java javaTutorial Why Does My Java Code Throw an 'Integer Number Too Large' Error for 600851475143?

Why Does My Java Code Throw an 'Integer Number Too Large' Error for 600851475143?

Nov 07, 2024 pm 10:08 PM

Why Does My Java Code Throw an

Error Message: "Integer Number Too Large" for 600851475143

The provided Java code aims to find the largest prime factor of a given number. However, when running the code for the input 600851475143, it throws an error. This error is caused by the fact that Java represents integers as 32-bit numbers by default. As a result, the number 600851475143, which exceeds the maximum value of a 32-bit integer, cannot be accommodated within this range.

To resolve this issue, we can use Java's long data type, which represents 64-bit integers and can handle larger numerical values. In the given code, simply replace the declaration of the input number with the following:

obj.function(600851475143L);
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By appending an "L" at the end of the number, we specify it as a long literal. This ensures that Java represents the number as a 64-bit integer, avoiding the "Integer number too large" error.

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