


Why Does a Line Break After a `return` Statement Cause `undefined` in JavaScript?
Understanding the Return Statement in JavaScript: Why Line Breaks Can Be Tricky
In JavaScript, the return statement is used to terminate the execution of a function and return a value to the calling context. However, a peculiar behavior arises when the return value is placed on a new line.
The Issue: Broken Return Statements
Consider the following code snippet:
<code class="javascript">function correct() { return 15; } function wrong() { return 15; } console.log("correct() called : " + correct()); console.log("wrong() called : " + wrong());</code>
In this example, the correct() function returns the expected value of 15, while the wrong() function returns undefined. This is surprising because in most other languages, the return statement followed by a new line would still return the correct value.
The Reason: JavaScript's Automatic Semicolon Insertion
The key to understanding this behavior lies in JavaScript's automatic semicolon insertion (ASI) feature. ASI is a mechanism that allows JavaScript to automatically insert semicolons at certain newline characters to ensure valid code execution.
When the return statement in wrong() is followed by a new line, ASI treats it as a separate statement. As a result, the code is interpreted as:
<code class="javascript">function wrong() { return; 15; }</code>
Since the first statement (return;) does not return a value, the wrong() function returns undefined.
The Solution: Wrapping the Return Value in Parentheses
To ensure that the return value is correctly returned even when on a new line, it is necessary to wrap it in parentheses. By doing this, ASI is prevented from inserting a semicolon and the return statement remains valid.
<code class="javascript">function wrong() { return( 15); }</code>
In this case, the parentheses indicate that the return value is part of the return statement. ASI does not insert a semicolon, and the wrong() function now returns 15 as intended.
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