Home Web Front-end JS Tutorial Why does using setTimeout in a promise chain break the chain, and how can it be fixed?

Why does using setTimeout in a promise chain break the chain, and how can it be fixed?

Oct 29, 2024 am 02:48 AM

Why does using setTimeout in a promise chain break the chain, and how can it be fixed?

Using setTimeout on Promise Chain

Promises provide a sequential ordering of asynchronous operations, allowing developers to work with callback-based code as if it were synchronous. However, introducing delays between operations in a promise chain can pose challenges.

Question:

In the provided code snippet, a delay is attempted using setTimeout, but it results in a JSON parse error. Why does this occur, and how can it be resolved?

<code class="javascript">...
getLinks('links.txt').then(function(links){
    let all_links = (JSON.parse(links));
    globalObj=all_links;

    return getLinks(globalObj["one"]+".txt");

}).then(function(topic){
    writeToBody(topic);
    setTimeout(function(){
         return getLinks(globalObj["two"]+".txt"); // without setTimeout it works fine
         },1000);
});
...</code>
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Answer:

The issue arises because setTimeout does not return a promise. By default, when you return a value from a promise chain, it is wrapped in a resolved promise object. However, since setTimeout returns a timer ID, the promise chain is broken, and the returned value is not treated as a promise.

To resolve this problem, the following approaches can be used:

1. Create a Delay Function Outside the Promise Chain:

Instead of using setTimeout, define a delay function that wraps the delay in a promise:

<code class="javascript">function delay(t, val) {
    return new Promise(resolve => setTimeout(resolve, t, val));
}</code>
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Updated Code:

<code class="javascript">...
getLinks('links.txt').then(function(links){
    let all_links = (JSON.parse(links));
    globalObj=all_links;

    return getLinks(globalObj["one"]+".txt");

}).then(function(topic){
    writeToBody(topic);
    // return a promise here that will be chained to prior promise
    return delay(1000).then(function() {
        return getLinks(globalObj["two"]+".txt");
    });
});
...</code>
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2. Add a Delay Method to the Promise Object:

A more elegant solution is to extend the Promise object with a delay method:

<code class="javascript">Promise.prototype.delay = function(t) {
    return this.then(function(val) {
        return delay(t, val);
    });
}</code>
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Updated Code:

<code class="javascript">...
getLinks('links.txt').then(function(links){
    let all_links = (JSON.parse(links));
    globalObj=all_links;

    return getLinks(globalObj["one"]+".txt");

}).then(function(topic){
    writeToBody(topic);
    // return a promise using the delay method
    return Promise.resolve().delay(1000).then(function() {
        return getLinks(globalObj["two"]+".txt");
    });
});
...</code>
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By using these techniques, you can introduce delays in promise chains without compromising the chaining behavior and avoiding runtime errors.

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