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Understanding Parenthesized Struct Initialization in Go
Home Backend Development Golang When Should You Use Parentheses for Struct Initialization in Go?

When Should You Use Parentheses for Struct Initialization in Go?

Oct 26, 2024 am 12:15 AM

 When Should You Use Parentheses for Struct Initialization in Go?

Understanding Parenthesized Struct Initialization in Go

In Go, struct initialization is typically done using curly braces { and }, as seen in the following example:

<code class="go">item1 := Item{1, "Foo"}</code>
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However, it is also possible to initialize structs using parentheses (), as shown below:

<code class="go">item2 := (Item{2, "Bar"})</code>
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Impact of Parenthesized Initialization:

Both forms of initialization result in identical Item values. Parenthesized initialization does not provide any specific advantages or changes in functionality.

When to Use Parentheses:

Parentheses become necessary when initializing structs within certain control structures, such as if statements. Without parentheses, the compiler may encounter a parsing ambiguity, resulting in an error. For instance:

<code class="go">if i := Item{3, "a"}; i.Id == 3 {
}</code>
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This code will cause a compile error because the compiler is unsure whether the opening brace { belongs to the composite literal or the body of the if statement. To resolve this ambiguity, parentheses can be added:

<code class="go">if i := (Item{3, "a"}); i.Id == 3 {
}</code>
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The parentheses clearly indicate that the composite literal is a complete expression, which is then assigned to the variable i within the if statement.

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