How to Parse Files and JSON Data from an HTTP Request in Golang?
Parsing Files and JSON Data from an HTTP Request in Go
In a web application, it's common to receive both files and JSON data in an HTTP request. To successfully process these elements, it's essential to understand how to parse them effectively.
The Problem
Consider a scenario where you have an AngularJS front end that sends a request to a Go backend. The request contains a file ("file") and JSON data ("doc"). Your goal is to parse both the PDF file and the JSON data from this request.
The Solution
To resolve this issue, you need to separately process both the file and JSON data. By utilizing http.(*Request).MultipartReader() and iterating over the parts using NextPart(), you can extract and parse each element.
Step 1: Create a Multipart Reader
<code class="go">mr, err := r.MultipartReader() if err != nil { http.Error(w, err.Error(), http.StatusInternalServerError) return }</code>
Step 2: Process Each Part
For each part in the multipart request:
<code class="go">part, err := mr.NextPart() if err == io.EOF { break } if err != nil { http.Error(w, err.Error(), http.StatusInternalServerError) return }</code>
Step 3: Extract File Data
If the part is a file (part.FormName() == "file"):
<code class="go">outfile, err := os.Create("./docs/" + part.FileName()) if err != nil { http.Error(w, err.Error(), http.StatusInternalServerError) return } defer outfile.Close() _, err = io.Copy(outfile, part) if err != nil { http.Error(w, err.Error(), http.StatusInternalServerError) return }</code>
Step 4: Parse JSON Data
If the part contains JSON data (part.FormName() == "doc"):
<code class="go">jsonDecoder := json.NewDecoder(part) err = jsonDecoder.Decode(&doc) if err != nil { http.Error(w, err.Error(), http.StatusInternalServerError) return }</code>
Step 5: Post-Processing
After parsing both file and JSON data, you can perform any necessary post-processing, such as saving it to a database or sending a response to the client.
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