How to optimize performance using HTTP file upload in Golang?
Best practices for optimizing Golang HTTP file upload performance: Set reasonable memory limits: r.MaxMemory = 32 << 20 // 32MB Use temporary files when storing large files: if err := r.ParseMultipartForm(32 << 20); err != nil { ... } Enable Goroutine concurrent processing: type multipartFile struct { ... }, func saveFilesConcurrently(files []multipartFile) { ... } Use compression algorithm to reduce file size :import "github.com/klauspost/compress/gzip", func compressImage(file multipartFile) { ... }Use CDN, cached response and code optimization
How to use HTTP file upload to optimize performance in Golang
Practice case: Optimizing image upload
Set reasonable memory limits
r.MaxMemory = 32 << 20 // 32MB
Use temporary files to store large files
if err := r.ParseMultipartForm(32 << 20); err != nil { return // 处理错误 } for _, file := range r.MultipartForm.File["images"] { f, err := os.CreateTemp("", "image-*.jpg") if err != nil { return // 处理错误 } if _, err := io.Copy(f, file); err != nil { return // 处理错误 } f.Close() // ... }
Enable Goroutine concurrent processing
type multipartFile struct { *multipart.FileHeader *os.File } func saveFilesConcurrently(files []multipartFile) { var wg sync.WaitGroup for _, file := range files { wg.Add(1) go func(f multipartFile) { defer wg.Done() // ... }(file) } wg.Wait() }
Use compression algorithm to reduce File Size
import "github.com/klauspost/compress/gzip" func compressImage(file multipartFile) (*os.File, error) { compressed, err := os.CreateTemp("", "image-*.jpg.gz") if err != nil { return nil, err } c := gzip.NewWriter(compressed) if _, err := io.Copy(c, file); err != nil { return nil, err } c.Close() return compressed, nil }
Additional Optimization Tips
- Use a CDN: Storing static files on a CDN can reduce server load.
-
Cache responses: Use the
Cache-Control
header to cache responses that typically do not change. - Code Optimization: Use performance analysis tools to identify and eliminate bottlenecks.
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