How to generate random integers within a specified range in Golang?

In Golang, use the Intn function in the rand package to generate a random integer within a specified range. The syntax is func Intn(n int) int, where n is an inclusive upper limit of random integers. By setting a random number seed and using Intn(100) + 1, you can generate a random integer between 1 and 100 (inclusive). However, it should be noted that the random integers generated by Intn are pseudo-random and cannot generate random integers with a specific probability distribution.

#How to generate a random integer within a specified range in Golang?

Generating random integers within a specified range in Golang is very simple, you can use the Intn function in the rand package.

Code syntax:

func Intn(n int) int

Where, n is the upper limit of random integers (not inclusive).

Practical case:

Let us generate a random integer between 1 and 100 (inclusive):

package main

import (
    "fmt"
    "math/rand"
    "time"
)

func main() {
    // 设置随机数种子
    rand.Seed(time.Now().UnixNano())

    // 生成一个在 1 到 100（含）之间的随机整数
    num := rand.Intn(100) + 1

    fmt.Println(num)
}

Run the above program, You will see a random integer between 1 and 100 printed on the command line.

Notes:

• #Intn The random integers generated by the function are pseudo-random, which means they are generated by the algorithm rather than Generated from a truly random source such as a coin toss.
• Intn The function cannot generate random integers with a specific probability distribution (such as the normal distribution). For such use cases, you need to use other random number generation methods.

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