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php ajax 用户登录退出

Jun 13, 2016 am 10:00 AM
ajax jquery php main and accomplish article user Log in combine quit

本文章主要讲到了jquery中的ajax和php结合,实现用户无刷新登录效果,有需要的朋友可以参考一下。

本例我们使用Mysql数据库,创建一张user表,表结构如下:

 代码如下 复制代码

CREATE TABLE `user` (
  `id` int(11) NOT NULL auto_increment,
  `username` varchar(30) NOT NULL COMMENT '用户名',
  `password` varchar(32) NOT NULL COMMENT '密码',
  `login_time` int(10) default NULL COMMENT '登录时间',
  `login_ip` varchar(32) default NULL COMMENT '登录IP',
  `login_counts` int(10) NOT NULL default '0' COMMENT '登录次数',
  PRIMARY KEY  (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8;
然后往user表中插入一条用户信息数据:

INSERT INTO `user` (`id`, `username`, `password`, `login_time`, `login_ip`, `login_counts`)
 VALUES(1, 'demo', 'fe01ce2a7fbac8fafaed7c982a04e229', '', '', 0);

用户在输入用户名和密码后,提示用户登录成功,并显示相关登录信息,如果点击“退出”,则退出到用户登录界面。

进入index.php,如果用户已登录则显示登录信息,如果未登录则显示登录框要求用户登录。

 代码如下 复制代码


     

用户登录


            if(isset($_SESSION['user'])){
      ?>
     

       

,恭喜您登录成功!


       

您这是第次登录本站。


       

上次登陆本站的时间是:

【退出】


     

     
     

         


         



         

             
         

     

     

注意在index.php文件头应该加上语句:session_start; 同时在head部分引入jquery库,以及包含global.js,您还可以为登录框写个漂亮的CSS样式,当然本例已经略微写了个简单的样式,请查看源码。

 代码如下 复制代码


 

global.js文件包括了将要实现的jquery代码。首先要做的就是让输入框获得焦点,像百度和google那样一打开,鼠标光标就在输入框内。使用代码如下:

 代码如下 复制代码

$("input:text,textarea,input:password").focus(function() {
    $(this).addClass("cur_select");
});
$("input:text,textarea,input:password").blur(function() {
    $(this).removeClass("cur_select");
});

用户登录
用户点击登录按钮后,首先要验证用户的输入不能为空,然后向后台login.php发送一个Ajax请求。当后台验证登录成功后,返回登录用户信息:如用户登录次数和上次登录时间等;如果登录失败,则返回登录失败信息。

 代码如下 复制代码
$(".btn").live('click',function(){
    var user = $("#user").val();
    var pass = $("#pass").val();
    if(user==""){
        $('
').html("用户名不能为空!").appendTo('.sub').fadeOut(2000);
        $("#user").focus();
        return false;
    }
    if(pass==""){
        $('
').html("密码不能为空!").appendTo('.sub').fadeOut(2000);
        $("#pass").focus();
        return false;
    }
    $.ajax({
        type: "POST",
        url: "login.php?action=login",
        dataType: "json",
        data: {"user":user,"pass":pass},
        beforeSend: function(){
            $('
').addClass("loading").html("正在登录...").css("color","#999")
.appendTo('.sub');
        },
        success: function(json){
            if(json.success==1){
                $("#login_form").remove();
                var div = "

"+json.user+",恭喜您登录成功!


               

您这是第"+json.login_counts+"次登录本站。


               

上次登录本站的时间是:"+json.login_time+"


                【退出】

";
                $("#login").append(div);
            }else{
                $("#msg").remove();
                $('
').html(json.msg).css("color","#999").appendTo('.sub')
.fadeOut(2000);
                return false;
            }
        }
    });
});

我在进行Ajax请求时,数据传输格式使用的是json,返回的数据也是json数据,使用JS将json数据解析,得到登录后的用户信息,然后通过append追加到#login元素下,完成登录操作。

用户退出
当点击“退出”时,向login.php发送一个Ajax请求,后台注销所有Session,页面重新回到登录界面。

 代码如下 复制代码

$("#logout").live('click',function(){
    $.post("login.php?action=logout",function(msg){
        if(msg==1){
             $("#result").remove();
             var div = "

 
            


            

id='pass' />


            

            
";
             $("#login").append(div);
        }
    });
});

login.php
根据前台提交的请求,登录时,获取用户输入的用户名和密码,并与数据库中对应的用户名和密码进行比对,如果比对成功,则将新的更新该用户登录信息,并组装json数据传给前台。

 代码如下 复制代码
session_start();
require_once ('connect.php');
 
$action = $_GET['action'];
if ($action == 'login') {  //登录
    $user = stripslashes(trim($_POST['user']));
    $pass = stripslashes(trim($_POST['pass']));
    if (empty ($user)) {
        echo '用户名不能为空';
        exit;
    }
    if (empty ($pass)) {
        echo '密码不能为空';
        exit;
    }
    $md5pass = md5($pass); //密码使用md5加密
    $query = mysql_query("select * from user where username='$user'");
 
    $us = is_array($row = mysql_fetch_array($query));
 
    $ps = $us ? $md5pass == $row['password'] : FALSE;
    if ($ps) {
        $counts = $row['login_counts'] + 1;
        $_SESSION['user'] = $row['username'];
        $_SESSION['login_time'] = $row['login_time'];
        $_SESSION['login_counts'] = $counts;
        $ip = get_client_ip(); //获取登录IP
        $logintime = mktime();
        $rs = mysql_query("update user set login_time='$logintime',login_ip='$ip',
login_counts='$counts'");
        if ($rs) {
            $arr['success'] = 1;
            $arr['msg'] = '登录成功!';
            $arr['user'] = $_SESSION['user'];
            $arr['login_time'] = date('Y-m-d H:i:s',$_SESSION['login_time']);
            $arr['login_counts'] = $_SESSION['login_counts'];
        } else {
            $arr['success'] = 0;
            $arr['msg'] = '登录失败';
        }
    } else {
        $arr['success'] = 0;
        $arr['msg'] = '用户名或密码错误!';
    }
    echo json_encode($arr); //输出json数据
}
elseif ($action == 'logout') {  //退出
    unset($_SESSION);
    session_destroy();
    echo '1';
}

当前台请求退出时,只需注销session就可以,并返回1给前台JS处理。注意上述代码中get_client_ip()是获取客户端IP的函数,限于篇幅未能列出。

 

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