Python压缩解压缩zip文件及破解zip文件密码的方法
python 的 zipfile 提供了非常便捷的方法来压缩和解压 zip 文件。
例如，在py脚本所在目录中，有如下文件：
readability/readability.js readability/readability.txt readability/readability-print.css readability/sprite-readability.png readability/readability.css
将 readability 目录中的文件压缩到脚本所在目录的 readability.zip 文件中，保持相同的文件结构，然后打印出生成的压缩包 的文件列表，再用两种方式分别解压文件到脚本所在目录的 output 目录和 output/bak 目录中。
脚本如下：
#!/usr/vin/env python
# coding: utf-8
"""
压缩和解压zip文件
"""
import os
import zipfile
def compress(zip_file, input_dir):
f_zip = zipfile.ZipFile(zip_file, 'w')
for root, dirs, files in os.walk(input_dir):
for f in files:
# 获取文件相对路径，在压缩包内建立相同的目录结构
abs_path = os.path.join(os.path.join(root, f))
rel_path = os.path.relpath(abs_path, os.path.dirname(input_dir))
f_zip.write(abs_path, rel_path, zipfile.ZIP_STORED)
def extract(zip_file, output_dir):
f_zip = zipfile.ZipFile(zip_file, 'r')
# 解压所有文件到指定目录
f_zip.extractall(output_dir)
# 逐个解压文件到指定目录
for f in f_zip.namelist():
f_zip.extract(f, os.path.join(output_dir, 'bak'))
def printdir(zip_file):
f_zip = zipfile.ZipFile(zip_file, 'r')
print '== printdir() ============================'
f_zip.printdir()
print
print '== namelist() ============================'
for f in f_zip.namelist():
print f
if __name__ == '__main__':
zip_file = 'readability.zip'
compress(zip_file, os.path.join(os.getcwd(), 'readability'))
printdirzip_file)
extract(zip_file, 'output')python暴力破解含密码的zip压缩文件
思路:
1.先自己生成一份txt的密码字典
2.然后读取出来，一个个的尝试,当密码错误是，程序会报错中断，所以密码错误，要使用pass
3.当解压缩成功后，中断程序，输出正确密码
import zipfile
import os
from threading import Thread
import time
#压缩文件的路径
path = r'C:\Users\Administrator\Desktop\moeMaid-master.zip'
#password='1234'
def pojie_zip(path,password):
if path[-4:]=='.zip':
#path = dir+ '\\' +file
#print path
zip = zipfile.ZipFile(path, "r",zipfile.zlib.DEFLATED)
#print zip.namelist()
try:
#若解压成功，则返回True,和密码
zip.extractall(path='C:\\Users\\Administrator\\Desktop\\',members=zip.namelist() , pwd=password)
print ' ----success!,The password is %s' % password
zip.close()
return True
except:
pass #如果发生异常，不报错
print 'error'
def get_pass():
#密码字典的路径
passPath='C:\\Users\\Administrator\\Desktop\\zip.txt'
passFile=open(passPath,'r')
for line in passFile.readlines():
password=line.strip('\n')
print 'Try the password %s' % password
if pojie_zip(path,password):
break
passFile.close()
if __name__=='__main__':
start=time.clock()
get_pass()
print "done (%.2f seconds)" % (time.clock() - start)
这是我解压缩一个5.4M文件的速度，其实时间都花在了解压缩上了
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