Home Database Mysql Tutorial mysql查询字段中带空格的值的sql语句

mysql查询字段中带空格的值的sql语句

Jun 07, 2016 pm 04:18 PM
mysql Field Inquire space statement

(1)mysql replace 函数 语法:replace(object,search,replace) 意思:把object中出现search的全部替换为replace 代码如下 update `news` set `content`=replace(`content`,' ','');//清除news表中content字段中的空格 这样就可以直接用like查询了。 (2)mysql

   (1)mysql replace 函数

  语法:replace(object,search,replace)

  意思:把object中出现search的全部替换为replace

 代码如下  

 

update `news` set `content`=replace(`content`,' ','');//清除news表中content字段中的空格 这样就可以直接用like查询了。

  (2)mysql trim 函数

  语法:trim([{BOTH | LEADING | TRAILING} [remstr] FROM] str)

  以下举例说明:

 代码如下  

mysql> SELECT TRIM(' phpernote  '); 

-> 'phpernote' 

mysql> SELECT TRIM(LEADING 'x' FROM 'xxxphpernotexxx'); 

-> 'phpernotexxx'

mysql> SELECT TRIM(BOTH 'x' FROM 'xxxphpernotexxx'); 

-> 'phpernote' 

mysql> SELECT TRIM(TRAILING 'xyz' FROM 'phpernotexxyz'); 

-> 'phpernotex' 

  当我们在使用sql查询的时候,如果数据库中的这个字段的值含有空格(字符串内部,非首尾),或者我们查询的字符串中间有空格,而字段中没有空格。那么我们很有可能就什么都查不到。假如有下面的一张表:

  表名

  id url title content

  这张表里面,第一和第二条记录的title部分是有空格的,如果我们并不知道,或者由于内容的不能,有无空格有很大的不确定性:

 代码如下  

select * from table where title = '李杨技术博客';
select * from table where title like '%李杨技术博客%';

  以上两句sql均无法查询出正确的结果,那么我们应该怎么写呢?

  请看下面:

 代码如下  

select * from table where trim(replace(title,' ','')) = trim(replace('李杨技术博客',' ',''));
select * from table where trim(replace(title,' ','')) like trim(replace('%李杨 技术博客%',' ',''));

  trim的作用是去掉字符串收尾的空格,replace的作用是去掉字符串内部的空格。

  这样就可以正确的进行匹配了,,如果不希望给mysql太多压力,条件部分的对空格的处理我们可以在程序中实现。

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