javascript - 必须关注微信公众平台才可以投票 SegmentFault
页面用户投票后
php 后台如何 判断 微信用户是否关注了 微信公共帐号呢
必须关注微信公众平台才可以投票
回复内容:
页面用户投票后
php 后台如何 判断 微信用户是否关注了 微信公共帐号呢
必须关注微信公众平台才可以投票
文档在这里
里面的subscribe
参数即可判断
全部数据如下:
<code>{ "subscribe": 1, "openid": "o6_bmjrPTlm6_2sgVt7hMZOPfL2M", "nickname": "Band", "sex": 1, "language": "zh_CN", "city": "广州", "province": "广东", "country": "中国", "headimgurl": "http://wx.qlogo.cn/mmopen/g3MonUZtNHkdmzicIlibx6iaFqAc56vxLSUfpb6n5WKSYVY0ChQKkiaJSgQ1dZuTOgvLLrhJbERQQ4eMsv84eavHiaiceqxibJxCfHe/0", "subscribe_time": 1382694957, "unionid": " o6_bmasdasdsad6_2sgVt7hMZOPfL" "remark": "", "groupid": 0 } </code>
和开发者模式无关的话可以是这个
点击查看文章
以微信登陆试试?
这个问题我在微信之前的版本就遇到过了,那时还没有获取用户信息的接口,我是这样处理的:
入口为微信返回的图文,在链接里面加上参数OpenId,后台处理判断有OpenId后保存session然后重定向到一个无get参数的url地址中,处理的时候判断session是否存在,存在就说明已经关注。这是我以前的办法,望能帮助到你。
判断改用户的openid是不是在自己数据库中就行了
这个必须获取到用户的openid才可以,使用这种方法得经过微信授权,把openid保存在自己的数据库

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