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Home Backend Development Golang Runtime optimization of regular expressions

Runtime optimization of regular expressions

Feb 11, 2024 am 10:15 AM

Runtime optimization of regular expressions

php editor Youzi will introduce you to the runtime optimization of regular expressions. Regular expressions are a powerful tool for string matching and processing, but can cause performance issues when working with large-scale data. In order to improve the execution efficiency of regular expressions, we can adopt some optimization strategies, such as using lazy matching, avoiding the use of backtracking, and using more precise matching patterns. These optimization techniques can help us use regular expressions more efficiently in actual development and improve program performance.

Question content

Most regular expressions are "constant" during their lifetime. Is it a good idea to use global regular expressions to speed up execution? For example:

func work() {
    r := regexp.mustcompile(`...`)
    if r.matchstring(...) {
        ...
    }
}
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Compare:

var r *regexp.Regexp

func work() {
    if r.MatchString(...) {
        ...
    }
}

func init() {
    r = regexp.MustCompile(`...`)
}
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Are there any meaningful differences between the two versions?

  1. Regular expressions are very cheap to compile, so from a cpu cost and garbage collection perspective, it is not worth using global regular expressions (assuming work() is called heavily)
  2. It is best to use global regular expressions when appropriate.

Which of the above is correct, or is the answer not simply black/white?

Workaround

It's not worth using a global regular expression if you only use the same regular expression once (e.g. "\d ") ->

If you often use the same regular expression (e.g. "\d ") ->, then it's worth using

func benchmark01(b *testing.b) {
    for i := 0; i < b.n; i++ {
        r := regexp.mustcompile(`\d+`)
        r.matchstring("aaaaaaa123bbbbbbb")
    }
}

func benchmark02(b *testing.b) {
    r := regexp.mustcompile(`\d+`)
    for i := 0; i < b.n; i++ {
        r.matchstring("aaaaaaa123bbbbbbb")
    }
}
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Benchmark01
Benchmark01-4             886909              1361 ns/op
Benchmark02
Benchmark02-4            5368380               232.8 ns/op
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