84669 person learning
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如:item['url']=response.xpath('a/@href')分析出一个链接,然后想从这个链接里的网页再获取一些元素,放入item['other']。应该怎么写,谢谢。
item['url']=response.xpath('a/@href')
item['other']
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def parse_page1(self, response): for url in urls: item = MyItem() item['url'] = url request = scrapy.Request(url,callback=self.parse_page2) # request = scrapy.Request("http://www.example.com/some_page.html",dont_filter=True,callback=self.parse_page2) request.meta['item'] = item yield request def parse_page2(self, response): item = response.meta['item'] item['other'] = response.xpath('/other') yield item
最后附上官方文档https://doc.scrapy.org/en/lat...中文翻译版http://scrapy-chs.readthedocs...
最后附上官方文档https://doc.scrapy.org/en/lat...
中文翻译版http://scrapy-chs.readthedocs...