2
885var data1 = {
"TemplateName": "数据规范",
"SummaryFields": [
{
"FieldName": "用户姓名",
"FieldCode": "UDF_F_935",
"Visable": true
},
{
"FieldName": "当前日期",
"FieldCode": "UDF_F_936",
"Visable": true
},
{
"FieldName": "ReportID",
"FieldCode": "ReportID",
"Visable": false
}
],
"Code": 0,
"Message": null
};
var data2 = {
"TotalCount": 2,
"ReturnData": [
{
"UDF_F_935": "超级管理员",
"UDF_F_936": "2009-05-01",
"UDF_F_938": "admin",
"UDF_F_942": "女",
"UDF_F_943": "丙",
"ReportID": "221"
},
{
"UDF_F_935": "超级管理员",
"UDF_F_936": "2009-05-01",
"UDF_F_938": "admin",
"UDF_F_942": "男",
"UDF_F_943": "乙",
"ReportID": "220"
}
],
"Code": 0,
"Message": null
};列表显示效果如下： 用户姓名:超级管理员, 当前日期:2009-05-01, ReportID:221 用户姓名:超级管理员, 当前日期:2009-05-01, ReportID:220
如何使用 javascript 构造列表相应的json数据？尽量提高性能
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写着写着，发现一个抖机灵的方法- -，不过不咋严格
//主要做的是键值替换 function generate(title, data){ var keys = {}; //先把键值对取出来 title.SummaryFields.forEach(function(e){ keys[e.FieldCode] = { name:e.FieldName, Visable:e.Visable }; }); //console.log(keys); //把目标数组序列化 var res = JSON.stringify(data.ReturnData); for(var key in keys){ //正则替换掉那些键值，没有的属性我无视了= = res = res.replace(new RegExp(key,'g'), keys[key].name); } //console.log(JSON.parse(res)); return JSON.parse(res); } console.log(generate(data1,data2));// es6 const map = data1.SummaryFields.reduce((r, t) => { r[t.FieldCode] = t.FieldName; return r; }, {}); const result = data2.ReturnData.map(m => { return Object.keys(m).reduce((r, key) => { const name = map[key]; if (name) { r[name] = m[key]; } return r; }, {}); });